1

我正在尝试侦听来自未知来源的 UDP 数据包。但无法绑定“未指定地址”(0.0.0.0 或 ::)

我已经尝试在 ::1 上收听。但从我测试的结果来看,这只适用于不通过网络接口的本地连接。

        public async void AwaitDiscoveryReply()
        {
            try
            {
                using (var client = new UdpClient(AddressFamily.InterNetworkV6))
                {
                    client.Connect(IPAddress.IPv6Any,4568);

                        var result = await client.ReceiveAsync();
                        Debug.WriteLine("Received DR");
                        var stateProtocol = StateProtocol.FromBytes(result.Buffer);
                        var robeatsDevice = new RobeatsDevice
                        {
                            Id = stateProtocol.DeviceId,
                            Name = stateProtocol.DeviceName,
                            EndPoint = client.Client.RemoteEndPoint,
                            StateProtocol = stateProtocol

                        };
                        OnDiscoveryReply(new DeviceDiscoveryEventArgs {RobeatsDevice = robeatsDevice});

                }
            }
            catch (Exception ex)
            {
                Debug.WriteLine(ex);
            }
        }

这不断抛出异常:The requested address is not valid in its context [::]:4568

4

1 回答 1

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UDP 套接字是无连接的。UDP 套接字实现上的“连接”方法,按照惯例(不要问我为什么)建立默认端点/过滤流量。如果你想从任何地址接收流量,你根本不需要“连接”。使用带有签名 UdpClient(Int32, AddressFamily) 的构造函数并删除 Connect() 调用:

public async void AwaitDiscoveryReply()
      {
          try
        {
            using (var client = new UdpClient(4568,AddressFamily.InterNetworkV6))
            {

                    var result = await client.ReceiveAsync();
                    Debug.WriteLine("Received DR");
                    var stateProtocol = StateProtocol.FromBytes(result.Buffer);
                    var robeatsDevice = new RobeatsDevice
                    {
                        Id = stateProtocol.DeviceId,
                        Name = stateProtocol.DeviceName,
                        EndPoint = client.Client.RemoteEndPoint,
                        StateProtocol = stateProtocol

                    };
                    OnDiscoveryReply(new DeviceDiscoveryEventArgs {RobeatsDevice = robeatsDevice});

            }
        }
        catch (Exception ex)
        {
            Debug.WriteLine(ex);
        }
    }
于 2019-04-18T17:06:29.427 回答