python - “列表[元素]”对象没有属性“名称”

Question

我有两个问题

1. 级别列表不包含名称或其他参数为什么此错误会出现在我收集的每个元素上
2. Urinals.Symbol.FamilyName("Type Comments").AsString() == "Urinal")： 不管用

from pyrevit.output import charts
from pyrevit import script
from pyrevit import revit, DB
from Autodesk.Revit.DB import FilteredElementCollector, BuiltInCategory
__context__ = 'zerodoc'

from System.Collections.Generic import List
doc = __revit__.ActiveUIDocument.Document
uidoc = __revit__.ActiveUIDocument

from rpw import db, ui, doc
from pyrevit.framework import List
from pyrevit import revit, DB
room_filter = "WORK"


import rpw
from rpw import doc, uidoc, DB

# GET ALL ROOMS IN MODEL
rooms = DB.FilteredElementCollector(doc).OfCategory(DB.BuiltInCategory.OST_Rooms)
Urinals = DB.FilteredElementCollector(doc).OfCategory(DB.BuiltInCategory.OST_PlumbingFixtures).WhereElementIsNotElementType().ToElements()
ub_count = 0
MRest_rooms = []
WRest_rooms = []
ADARest_rooms = []
Urinal_count = 0

#for u in Urinals:
#   if (Urinals.Symbol.FamilyName("Type Comments").AsString() == "Urinal"):
#    Urinal_count +=1
for r in rooms:
    if (r.Level.Name != 'CONTAINER LEVEL') and (r.LookupParameter("Name").AsString() == "M RESTROOM"):
        MRest_rooms.append(r)
    if (r.Level.Name != 'CONTAINER LEVEL') and (r.LookupParameter("Name").AsString() == "W RESTROOM"):
        WRest_rooms.append(r)

print "Number of Male Rest Room =",len(MRest_rooms)
print "Number of Female Rest Room =", len(WRest_rooms)

Level = DB.FilteredElementCollector(doc).OfCategory(DB.BuiltInCategory.OST_Levels).WhereElementIsNotElementType().ToElements()
print "Number of Level =",len(Level)
for i in Level:
 a = Level.Name
 print a

Answer 1

在调试器中查看它，您将自己看到。

Answer 2

您的错误是这一行：

Level = DB.FilteredElementCollector(doc).OfCategory(DB.BuiltInCategory.OST_Levels).WhereElementIsNotElementType().ToElements()
print "Number of Level =",len(Level)
for i in Level:
 a = Level.Name
 print a

它应该是：

Level = DB.FilteredElementCollector(doc).OfCategory(DB.BuiltInCategory.OST_Levels).WhereElementIsNotElementType().ToElements()
print "Number of Level =",len(Level)
for i in Level:
 a = i.Name
 print a

在你调用where实际上是一个级别列表的for循环内部。因此例外。Level.NameLevel

注释掉的代码也有同样的问题：

for u in Urinals:
   if (Urinals.Symbol.FamilyName("Type Comments").AsString() == "Urinal"):
    Urinal_count +=1

用。。。来代替：

for u in Urinals:
   if (u.Symbol.FamilyName("Type Comments").AsString() == "Urinal"):
    Urinal_count +=1