4

我想激活当前的网络接口并连接到互联网。

实际上，我可以检查网络是否启动以及是否不是环回网络。

  foreach(QNetworkInterface interface, QNetworkInterface::allInterfaces())
    {
        if (interface.flags().testFlag(QNetworkInterface::IsUp) && !interface.flags().testFlag(QNetworkInterface::IsLoopBack))
            foreach (QNetworkAddressEntry entry, interface.addressEntries())
            {
            if ( interface.hardwareAddress() != "00:00:00:00:00:00" && entry.ip().toString().contains("."))
                items << interface.name() + " "+ entry.ip().toString() +" " + interface.hardwareAddress();
        }

结果：

"en1 3.3.3.52 D4:9A:20:61:1F:72" 
"vmnet1 192.168.169.1 00:50:56:C0:00:01" 
"vmnet8 192.168.210.1 00:50:56:C0:00:08"

事实上它可以工作，但我也发现了 VM 接口。我只想选择 WLAN 接口和以太网接口。

4

5 回答 5

8

很抱歉重新提出一个老问题，但我自己只是在思考这个问题并想出了一个解决方案：

QList<QString> possibleMatches;
QList<QNetworkInterface> ifaces = QNetworkInterface::allInterfaces();
if ( !ifaces.isEmpty() )
{
  for(int i=0; i < ifaces.size(); i++)
  {
    unsigned int flags = ifaces[i].flags();
    bool isLoopback = (bool)(flags & QNetworkInterface::IsLoopBack);
    bool isP2P = (bool)(flags & QNetworkInterface::IsPointToPoint);
    bool isRunning = (bool)(flags & QNetworkInterface::IsRunning);

    // If this interface isn't running, we don't care about it
    if ( !isRunning ) continue;
    // We only want valid interfaces that aren't loopback/virtual and not point to point
    if ( !ifaces[i].isValid() || isLoopback || isP2P ) continue;
    QList<QHostAddress> addresses = ifaces[i].allAddresses();
    for(int a=0; a < addresses.size(); a++)
    {
      // Ignore local host
      if ( addresses[a] == QHostAddress::LocalHost ) continue;

      // Ignore non-ipv4 addresses
      if ( !addresses[a].toIPv4Address() ) continue;

      QString ip = addresses[a].toString();
      if ( ip.isEmpty() ) continue;
      bool foundMatch = false;
      for (int j=0; j < possibleMatches.size(); j++) if ( ip == possibleMatches[j] ) { foundMatch = true; break; }
      if ( !foundMatch ) { possibleMatches.push_back( ip ); qDebug() << "possible address: " << ifaces[i].humanReadableName() << "->" << ip; }
    }
  }
}
// Now you can peek through the entries in possibleMatches
// With VMWare installed, I get two entries, and the first one is the correct one.
// If you wanted to test which one has internet connectivity, try creating a tcp
// connection to a known internet service (e.g. google.com) and if the connection
// is successful, check the following on the tcp connection
/*
if ( socket->localAddress().toIPv4Address() )
{
  for(int c=0; c < possibleMatches.size(); c++) if ( socket->localAddress().toString() == possibleMatches[c] ) { qDebug() << "Your LAN IP:" << possibleMatches[c]; }
}
*/

你可能想让它更健壮一点，所以代码可以同时跟踪接口和 IP 地址，但这可能是不必要的，因为我很确定一个接口不能保存多个 IP 地址，并且没有两个接口可以具有相同的 IP 地址（如果我在这个假设上错了，请纠正我）。

于 2013-05-29T18:57:17.760 回答
4

我知道这个问题很老，但我正在做类似的事情。

这是我的解决方案：

  foreach(QNetworkInterface interface, QNetworkInterface::allInterfaces())
    {
        if (interface.flags().testFlag(QNetworkInterface::IsUp) && !interface.flags().testFlag(QNetworkInterface::IsLoopBack))
            foreach (QNetworkAddressEntry entry, interface.addressEntries())
            {
            if ( interface.hardwareAddress() != "00:00:00:00:00:00" && entry.ip().toString().contains(".") && !interface.humanReadableName().contains("VM"))
                items << interface.name() + " "+ entry.ip().toString() +" " + interface.hardwareAddress();
        }

我刚刚添加了

&& !interface.humanReadableName().contains("VM")

到您的第二个 if 语句。现在它不会列出包含字符串“vm”的适配器。

希望这对其他人也有帮助。

于 2015-05-22T14:58:25.743 回答
1

使用enum QNetworkInterface::InterfaceFlag获取此信息。

QNetworkInterface::IsUp         0x1 the network interface is active
QNetworkInterface::IsRunning    0x2 the network interface has resources allocated
QNetworkInterface::CanBroadcast 0x4 the network interface works in broadcast mode
QNetworkInterface::IsLoopBack   0x8 the network interface is a loopback interface: that is, it's a virtual interface whose destination is the host computer itself
QNetworkInterface::IsPointToPoint   0x10    the network interface is a point-to-point interface: that is, there is one, single other address that can be directly reached by it.
QNetworkInterface::CanMulticast 0x20    the network interface supports multicasting

来自Qt 4.7 文档。

于 2011-04-06T20:04:47.953 回答
0 
for windows
// return -- interface ipv4 entry, interface type
QList<QPair<QHostAddress,QNetworkInterface::InterfaceType>> getActiveNetworks()
{
    QProcess m_process;
    QStringList param;param<<"Get-NetAdapter -physical | where status -eq 'up' |Format-List -Property \"MacAddress\"";
    m_process.start("powershell",param);
    m_process.waitForFinished();
    QString result =  m_process.readAllStandardOutput();
    QStringList resultList = result.split("\r\n\r\n");
    resultList.removeAll("");
    QStringList macAddressList;
    for(auto maclist :resultList)
    {
        QString temp = maclist.split(':').at(1);
        temp.remove(' ');
        temp.replace('-',':');
        macAddressList.append(temp);
    }
    QList<QPair<QHostAddress,QNetworkInterface::InterfaceType>> networks;
    for(auto interface:QNetworkInterface::allInterfaces())
    {
        if(macAddressList.contains(interface.hardwareAddress()))
            for(QNetworkAddressEntry address:interface.addressEntries())
               if(address.ip().toIPv4Address())
                networks.append(QPair<QHostAddress,QNetworkInterface::InterfaceType>
                            (address.ip(),interface.type()));
    }
    return networks;
}
于 2020-11-11T07:53:37.967 回答
-1

使用 建立 TCP 连接QTcpSocket。接下来，获取它的.localAddress. 您可能会发现 Internet 的不同部分对应不同的本地地址。

于 2011-04-07T08:44:08.997 回答