1

我在 userSchema.graphql 文件中有用户模式；

  id: String!
  userName: String!
  email: String!
  password: String!
}

我有不同的 schema.graphql 文件用于登录和注册

我无法访问登录/注册模式中的用户模式

type Query{
    hi: String!
}
type Mutation {
    register( userName: String!, email: String!, password: String! ): User
}

我正在使用来自 graphql 工具的模式拼接并从 merge-graphql-schema 包中合并 typeDefs 和解析器

import "graphql-import-node";
import { GraphQLSchema } from "graphql";
import { mergeResolvers, mergeTypes } from "merge-graphql-schemas";
import * as userSchema from './modules/auth/shared/schema.graphql'
import * as registerTypedefs from "./modules/auth/register/schema.graphql";
import registerResolver from "./modules/auth/register/registerResolver";

import * as todoTypedefs from "./modules/todo/schema.graphql";
import todoResolver from "./modules/todo/todoResolver";

import { makeExecutableSchema } from "graphql-tools";

const schema: GraphQLSchema = makeExecutableSchema({
  typeDefs: mergeTypes([userSchema, registerTypedefs, todoTypedefs], { all: true }),
  resolvers: mergeResolvers([registerResolver, todoResolver])
});
export default schema;

我收到错误

Error: Field register: Couldn't find type User in any of the schemas.
    at collectNode (E:\graphql\express-apollo-server\node_modules\graphql-import\src\definition.ts:154:15)
    at E:\graphql\express-apollo-server\node_modules\graphql-import\src\definition.ts:135:7
    at Array.forEach (<anonymous>)

编辑 我使用了'merge-graphql-schemas'中的fileLoader，它工作得很好

import { mergeResolvers, mergeTypes, fileLoader } from "merge-graphql-schemas";


const typesArray = fileLoader(path.join(__dirname, './modules/**/*.graphql'), { recursive: true })

const schema: GraphQLSchema = makeExecutableSchema({
  typeDefs: mergeTypes(typesArray, { all: true }),
  resolvers: mergeResolvers([registerResolver, loginRegister, todoResolver, storyResolver])
});
4

1 回答 1

1

我在我的项目中使用了一个 require-graphql 文件和 lodash 合并，同样的场景也适用于我。

import requireGraphQLFile from 'require-graphql-file';
import { merge } from 'lodash';

const $userSchema = requireGraphQLFile('./schema/yourFolder/userSchema.graphql');
const $registerTypedefs= requireGraphQLFile('./schema/yourFolder/register.graphql');

import registerResolver from "./modules/auth/register/registerResolver";
import todoResolver from "./modules/todo/todoResolver";

const schema: GraphQLSchema = makeExecutableSchema({
   typeDefs: [$userSchema, 
              $registerTypedefs,
              todoTypedefs
             ],              
   resolvers: merge(registerResolver, todoResolver)
});

希望这会有所帮助。

于 2019-04-16T17:38:12.873 回答