我想在 QAbstractItemModel 的 GUI 中显示单个项目及其角色。在手册中我只能找到如何显示整个模型。
显示单个项目正在工作,但是当模型中的数据发生更改时,GUI 中的数据不会更新。
模型在 setData() 函数中发出 dataChanged()。
模型中的对象:
#ifndef DATASOURCEOBJECT_H
#define DATASOURCEOBJECT_H
#include <QString>
#include <QVariantMap>
class DataSourceObject
{
public:
DataSourceObject(const int &id=0, const QString &name="", const QString &displayname="", const double &value=0.0);
DataSourceObject(const QJsonObject &obj);
int id() const;
void setId(int id);
QString name() const;
void setName(const QString &name);
QString unit() const;
void setUnit(const QString &unit);
double value() const;
void setValue(double value);
QVariantMap toMap() const;
private:
int m_id;
QString m_name;
QString m_unit;
double m_value;
};
#endif // DATASOURCEOBJECT_H
模型标题:
#ifndef DATASOURCEMODEL_H
#define DATASOURCEMODEL_H
#include "datasourceobject.h"
#include <QAbstractListModel>
class DataSourceModel : public QAbstractListModel
{
Q_OBJECT
public:
enum datasourceRoles {
idRole = Qt::UserRole ,
nameRole,
unitRole,
valueRole
};
explicit DataSourceModel(QObject *parent = nullptr);
void addDataSourceObject(const DataSourceObject &dataSourceObject);
Q_INVOKABLE QVariantMap get(int row) const;
int rowCount(const QModelIndex &parent = QModelIndex()) const override;
Q_INVOKABLE QVariant data(const QModelIndex &index, int role = Qt::DisplayRole) const override;
bool setData(const QModelIndex &index, const QVariant &value,
int role = Qt::EditRole) override;
Qt::ItemFlags flags(const QModelIndex& index) const override;
QHash<int, QByteArray> roleNames() const override;
//bool checkIndex(const QModelIndex &index) const;
private:
QList<DataSourceObject> m_DataSourceObjects;
};
#endif // DATASOURCEMODEL_H
型号 cpp:
#include "datasourcemodel.h"
DataSourceModel::DataSourceModel(QObject *parent)
: QAbstractListModel(parent)
{
}
QVariantMap DataSourceModel::get(int row) const
{
return m_DataSourceObjects[row].toMap();
}
void DataSourceModel::addDataSourceObject(const DataSourceObject &dataSourceObject)
{
beginInsertRows(QModelIndex(), rowCount(), rowCount());
m_DataSourceObjects << dataSourceObject;
endInsertRows();
}
int DataSourceModel::rowCount(const QModelIndex &parent) const
{
if (parent.isValid())
return 0;
return m_DataSourceObjects.count();
}
QVariant DataSourceModel::data(const QModelIndex &index, int role) const
{
if(index.row() < 0 || index.row() >= m_DataSourceObjects.count() || !index.isValid())
return QVariant();
const DataSourceObject &dataSourceObject = m_DataSourceObjects[index.row()];
if (role == idRole)
return dataSourceObject.id();
else if (role == nameRole)
return dataSourceObject.name();
else if (role == unitRole) {
return dataSourceObject.unit();
}
else if (role == valueRole)
return dataSourceObject.value();
return QVariant();
}
bool DataSourceModel::setData(const QModelIndex &index, const QVariant &value, int role)
{
DataSourceObject &dataSourceObject = m_DataSourceObjects[index.row()];
if (data(index, role) != value) {
if(role == idRole)
dataSourceObject.setId(value.toInt());
else if(role == nameRole)
dataSourceObject.setName(value.toString());
else if(role == unitRole)
dataSourceObject.setUnit(value.toString());
else if(role == valueRole)
dataSourceObject.setValue(value.toDouble());
emit dataChanged(index, index, QVector<int>() << role);
return true;
}
return false;
}
Qt::ItemFlags DataSourceModel::flags(const QModelIndex &index) const
{
if (!index.isValid())
return Qt::NoItemFlags;
return Qt::ItemIsEditable; // FIXME: Implement me!
}
QHash<int, QByteArray> DataSourceModel::roleNames() const
{
QHash<int, QByteArray> roles;
roles[idRole] = "id";
roles[nameRole] = "name";
roles[unitRole] = "unit";
roles[valueRole] = "value";
return roles;
}
我试图像这样访问 QML 中的单个项目:
Text {
text: dataSourceModel.data(dataSourceModel.index(88,0),259).toFixed(decimalplaces)
}
这显示了数据的角色 259(valueRole),但文本在更改时不会更新。
我试图从 QObject 派生模型内部的对象,以使用 Q_INVOKABLE,但是当从 QOBject 派生时,我无法编译它。C:\Qt\5.10.0\mingw53_32\include\QtCore\qlist.h:435: Fehler:使用已删除的函数 'DataSourceObject::DataSourceObject(const DataSourceObject&)' if (QTypeInfo::isLarge || QTypeInfo::isStatic) n->v = new T(t);
^