首先,感谢指点!部分答案如下......
到目前为止我所拥有的......首先是一些脚手架:
# Connect to our db through DBIx::Class
my $schema = My::Schema->connect('dbi:SQLite:/home/me/accounts.db');
# See also BEGIN { $ENV{DBIC_TRACE} = 1 }
$schema->storage->debug(1);
# Create an instance of our subclassed (see below)
# DBIx::Class::Storage::Statistics class
my $stats = My::DBIx::Class::Storage::Statistics->new();
# Set the debugobj object on our schema's storage
$schema->storage->debugobj($stats);
My::DBIx::Class::Storage::Statistics 的定义是:
package My::DBIx::Class::Storage::Statistics;
use base qw<DBIx::Class::Storage::Statistics>;
use Data::Dumper qw<Dumper>;
use SQL::Statement;
use SQL::Parser;
sub query_start {
my ($self, $sql_query, @params) = @_;
print "The original sql query is\n$sql_query\n\n";
my $parser = SQL::Parser->new();
my $stmt = SQL::Statement->new($sql_query, $parser);
#printf "%s\n", $stmt->command;
print "The parameters for this query are:";
print Dumper \@params;
}
这解决了有关如何挂钩以使我的 SQL 查询“漂亮化”的问题。
然后我运行一个查询:
my $rs = $schema->resultset('SomeTable')->search(
{
'email' => $email,
'others.some_col' => 1,
},
{ join => 'others' }
);
$rs->count;
但是 SQL::Parser 对 DBIx::Class 生成的 SQL 不满意:
The original sql query is
SELECT COUNT( * ) FROM some_table me LEFT JOIN others other_table ON ( others.some_col_id = me.id ) WHERE ( others.some_col_id = ? AND email = ? )
SQL ERROR: Bad table or column name '(others' has chars not alphanumeric or underscore!
SQL ERROR: No equijoin condition in WHERE or ON clause
那么......有没有比 SQL::Parser 更好的解析器来完成这项工作?