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我实际上正在快速构建一个应用程序。问题是应用程序应该从经度纬度获取子位置并检查该子位置是否是数组的一部分，但我无法获得子位置

这里的任何专业人士都可以帮助我吗

这是使用的经度纬度

let loc: CLLocation = CLLocation(latitude:43.60089111328125, longitude: 3.875329601741884)

ceo.reverseGeocodeLocation(loc, completionHandler: {(placemarks, error) in
                        if (error != nil)
                        {
                            print("reverse geodcode fail: \(error!.localizedDescription)")
                        }
                        let pm = placemarks! as [CLPlacemark]

                        if pm.count > 0 {
                            let pm = placemarks![0]
                            addressString = ""

                            if pm.name != nil {
                                addressString += pm.name! + ", "
                            }

                            if pm.isoCountryCode != nil {
                                addressString += pm.isoCountryCode! + ", "
                            }

                            if pm.country != nil {
                                addressString += pm.country! + ", "
                            }

                            if pm.postalCode != nil {
                                addressString += pm.postalCode! + ", "
                            }

                            if pm.administrativeArea != nil {
                                addressString += pm.administrativeArea! + ", "
                            }
                            if pm.subAdministrativeArea != nil {
                                addressString += pm.subAdministrativeArea! + ", "
                            }

                            if pm.locality != nil {
                                addressString += pm.locality! + ", "
                            }

                            if pm.subLocality != nil {
                                addressString += pm.subLocality! + ", "
                            }

                            if pm.thoroughfare != nil {
                                addressString += pm.thoroughfare! + ", "
                            }

                            if pm.subThoroughfare != nil {
                                addressString += pm.subThoroughfare! + ", "
                            }
                            if pm.areasOfInterest != nil {
                                print(pm.areasOfInterest!)
                            }

     print(pm.addressDictionary)
}
})

哪个应该将 GAMBETTA 作为 subLocality 返回，但什么都没有。

4

2 回答 2

0

你可以试试，它会帮助你。

   let newlocation: CLLocation = CLLocation(latitude:43.60089111328125, longitude: 3.875329601741884)


        let geoCoder = CLGeocoder()
        geoCoder.reverseGeocodeLocation(newlocation, completionHandler: { (placemarks, error) -> Void in

            // Place details
            var placeMark: CLPlacemark!
            placeMark = placemarks?[0]

            print(placeMark.subLocality as Any)

            // Address dictionary
            print(placeMark.addressDictionary as Any)

            //City
            if let city = placeMark.addressDictionary!["City"] as? String {
                print("city : \(city)")
            }

     })
于 2019-04-12T15:19:19.077 回答
0

您可以Geocoder根据将返回 a 的位置坐标使用反向地理编码CLPlacemark ，然后您可以检查subLocality是否存在，如下所示：

let geoCoder = CLGeocoder()
geoCoder.reverseGeocodeLocation(loc, completionHandler: { placemarks, error in
    // Place details
    guard let placeMark = placemarks?.first else { return }

    // SubLocality
    if let subLocality = placeMark.subLocality {
      // Do something if exists
    }
})
于 2019-04-12T14:57:03.330 回答