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我正在尝试实现从一个操作读取用户输入并在其他屏幕中读取,例如:

    user: xx
    Bixby: who's there?
    user: yyy
    Bixby: yyy who?

I am able to read user input yyy but unable to pass in different actions to display yyy who.

您能否帮助或指导我做错了什么或做这种胶囊的最佳方法是什么?

提前致谢。

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1 回答 1

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这就是我将如何模拟您可能试图实现的行为。

Concepts 
 - Joke 
    - JokeQuestion (posed by 'Bixby')
    - JokeAnswer (answered by User)
Views
 - JokeResultView
 - JokeAnswerInputView
Layouts
 - JokeLayout
 - JokeQuestionLayout
 - JokeAnswerLayout
Action (all of these Actions take Joke as input AND output the Joke back)
 - GetJokeAnswerFromUser (get an Answer concept from the user and update the Interaction concept)
 - ShowJokeQuestionToUser (show the next JokeQuestion to the user)
Other Actions as needed?

通过这种安排,您始终可以通过 Joke Concept 访问 JokeQuestion(s) 和 JokeAnswer(s)。JokeResultView 将驱动用户在屏幕上看到的内容,您可以在您的实现中构建某种逻辑来表示笑话的开始和结束等。

试试这个,看看它是否有帮助。

于 2019-04-15T21:07:19.533 回答