我正在尝试从 .txt 文件在 Python 中生成一个 {single-key : [multi-value]} 字典。
这是文本文件(制表符分隔),
A02.835.583.748 A02.880 0.818181818181818
A02.835.583.748 A02.513 0.818181818181818
A02.835.583.748 A01.378.800.750 0.636363636363636
A02.835.583 A02.880 0.863636363636364
A02.835.583 A02.513 0.863636363636364
A02.835.583 A01.378.800.750 0.681818181818182
A01.378.800.750 A02.880 0.727272727272727
A01.378.800.750 A02.513 0.727272727272727
A01.378.800.750 A01.378.800.750 1
同样,我使用“defaultdict()”函数,但不知何故我无法正确生成字典。我可以通过这个生成字典,但这很奇怪。因此,我从这本奇怪的字典中获取其中一个键。
print(anaDict.get('A02.835.583.748'))
输出:
['A02.880=0.818181818181818', [...], ['A02.513=0.818181818181818'], ['A01.378.800.750=0.636363636363636']]
然而,这个字典中的 [...] 实际上是以一种初始的方式嵌套同一个键的其他值。
我写的代码,
anaDict = defaultdict()
anaSet = set()
with open(f, 'r') as anaFile:
if '148' in f:
for line in anaFile:
key = line.split('\t')[0].rstrip()
conclusionVal = line.split('\t')[1].strip()
simScore = line.split('\t')[2].strip()
value = [conclusionVal + "=" + simScore]
if key not in anaDict:
print("Here it goes: " , key, value)
anaDict[key] = value
if key in anaDict:
print("Different value: ", key, value)
anaDict[key].append(value)
print(anaDict.get('A02.835.583.748'))
我希望代码生成以下字典(显示为键值对)。
A02.835.583.748 : [A02.880 = 0.818181818181818 , A02.513 = 0.818181818181818, A01.378.800.750 = 0.636363636363636]
A02.835.583 : [A02.880 = 0.863636363636364, A02.513 = 0.863636363636364, A01.378.800.750 = 0.681818181818182]
A01.378.800.750 : [A02.880 = 0.727272727272727, A02.513 = 0.727272727272727, A01.378.800.750 = 1]
我无法弄清楚我做错了什么。我会为任何帮助或方向提供帮助。