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我有一个代码正在运行并成功打印 ATR、UID 和状态，但是，程序在检测并打印 UID 后结束。如何在检测到并等待移除和插入不同的卡（或同一张卡）后重置我的代码

我尝试过使用 while 循环，但这会导致程序多次打印 ATR、UID 和状态，并且当卡被移除时，程序会因错误而终止。

from smartcard.CardRequest import CardRequest
from smartcard.Exceptions import CardRequestTimeoutException
from smartcard.CardType import AnyCardType
from smartcard import util

WAIT_FOR_SECONDS = 60

# respond to the insertion of any type of smart card
card_type = AnyCardType()

# create the request. Wait for up to x seconds for a card to be attached
request = CardRequest(timeout=WAIT_FOR_SECONDS, cardType=card_type)

# listen for the card
service = None
try:
    service = request.waitforcard()
except CardRequestTimeoutException:
    print("ERROR: No card detected")
    exit(-1)

# when a card is attached, open a connection
conn = service.connection
conn.connect()

# get and print the ATR and UID of the card
get_uid = util.toBytes("FF CA 00 00 00")
print("ATR = {}".format(util.toHexString(conn.getATR())))
data, sw1, sw2 = conn.transmit(get_uid)
uid = util.toHexString(data)
status = util.toHexString([sw1, sw2])
print("UID = {}\tstatus = {}".format(uid, status))

它尝试过的修复（这会继续打印，当我取出卡时它会终止（已解决））：

from smartcard.CardRequest import CardRequest
from smartcard.Exceptions import CardRequestTimeoutException
from smartcard.CardType import AnyCardType
from smartcard import util

WAIT_FOR_SECONDS = 60
# respond to the insertion of any type of smart card
card_type = AnyCardType()

# create the request. Wait for up to x seconds for a card to be attached
request = CardRequest(timeout=WAIT_FOR_SECONDS, cardType=card_type)

while True:
    # listen for the card
    service = None
    try:
        service = request.waitforcard()
    except CardRequestTimeoutException:
        print("ERROR: No card detected")
        # could add "exit(-1)" to make code terminate

    # when a card is attached, open a connection
    try:
        conn = service.connection
        conn.connect()

        # get the ATR and UID of the card
        get_uid = util.toBytes("FF CA 00 00 00")
        data, sw1, sw2 = conn.transmit(get_uid)
        uid = util.toHexString(data)
        status = util.toHexString([sw1, sw2])


        # print the ATR and UID of the card
        print("ATR = {}".format(util.toHexString(conn.getATR())))
        print("UID = {}\tstatus = {}".format(uid, status))
    except:
        print("no connection")

问题是我不知道如何创建一个打印一次的循环。打印 UID 后，它等待卡被移除并输入另一个卡，然后循环重置。

编辑：我设法使代码重置，但是，我不知道如何让程序打印一次而不是继续打印。有什么建议么？

我希望代码在智能卡出现后打印一次，然后当智能卡被移除时，重置并再次收听智能卡。

4

1 回答 1

2

这会做到这一点，但它会使 UI 无法点击，因为它仍在后台运行。

# respond to the insertion of any type of smart card
card_type = AnyCardType()

# create the request. Wait for up to x seconds for a card to be attached
request = CardRequest(timeout=0, cardType=card_type)
hasopened = False

while True:
    # listen for the card
    service = None
    try:
        service = request.waitforcard()
    except CardRequestTimeoutException:
        print("ERROR: No card detected")
        ui.lineEdit_2.setText('NO CARD DETECTED')
        ui.lineEdit_2.setStyleSheet("background-color: #e4e0e0;\n" "color: #000000;")
        ui.label_5.setStyleSheet("background-color: #ff0000")

    # could add "exit(-1)" to make code terminate

    # when a card is attached, open a connection
    try:
        conn = service.connection
        conn.connect()

        # get the ATR and UID of the card
        get_uid = util.toBytes("FF CA 00 00 00")
        data, sw1, sw2 = conn.transmit(get_uid)
        uid = util.toHexString(data)
        status = util.toHexString([sw1, sw2])

        # print the ATR and UID of the card
        if conn and not hasopened:
            print("ATR = {}".format(util.toHexString(conn.getATR())))
            print("UID = {}\tstatus = {}".format(uid, status))
            ui.lineEdit_2.setText(uid)
            ui.lineEdit_2.setStyleSheet("background-color: #e4e0e0;\n" "color: #000000;")
            ui.label_5.setStyleSheet("background-color: #86dc3d")

            hasopened=True
    except:
        print("no connection")
于 2021-12-13T07:23:46.947 回答