我稍微修改了解决方案,在@Larme 和@vadian 指出的答案中找到。两个答案都以相同的算法结束。我只想看看这集的内容。是的,想要这样做并不常见。事实证明,获取所有元素的唯一方法CharacterSet
是遍历所有可能的 unicode 标量并检查它们是否属于该集合。Set
在我们可以在s和 s之间切换Array
甚至Dictionaries
如此简单的词中,我感觉很奇怪。修改的原因是为了加快功能。我的粗略实验表明,即使我们最终创建了一个字符串,使用标量也能快 30%。
extension CharacterSet {
func allUnicodeScalars() -> [UnicodeScalar] {
var result: [UnicodeScalar] = []
for plane in Unicode.UTF8.CodeUnit.min...16 where self.hasMember(inPlane: plane) {
for unicode in Unicode.UTF32.CodeUnit(plane) << 16 ..< Unicode.UTF32.CodeUnit(plane + 1) << 16 {
if let uniChar = UnicodeScalar(unicode), self.contains(uniChar) {
result.append(uniChar)
}
}
}
return result
}
}
// Testing and timing
printTimeElapsedWhenRunningCode(title:"allUnicodeScalars()") {
print(String.UnicodeScalarView(chSet.allUnicodeScalars()))
}
// Time elapsed for allUnicodeScalars(): 1.936843991279602 s.
printTimeElapsedWhenRunningCode(title:"allCharacters()") {
print(String(chSet.allCharacters()))
}
// Time elapsed for allCharacters(): 2.9846099615097046 s.
//Timing functions (for reference):
private func printTimeElapsedWhenRunningCode(title:String, operation:()->()) {
let startTime = CFAbsoluteTimeGetCurrent()
operation()
let timeElapsed = CFAbsoluteTimeGetCurrent() - startTime
print("Time elapsed for \(title): \(timeElapsed) s.")
}
private func timeElapsedInSecondsWhenRunningCode(operation: ()->()) -> Double {
let startTime = CFAbsoluteTimeGetCurrent()
operation()
let timeElapsed = CFAbsoluteTimeGetCurrent() - startTime
return Double(timeElapsed)
}
UPD:是的,这个问题是重复的,并且存在更好的答案。