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我想通过reticulate在 R 中使用 python 拆分波形文件，从 Python 中提取示例脚本，如何将 .wav 文件拆分为多个 .wav 文件

 from pydub import AudioSegment
    t1 = t1 * 1000 #Works in milliseconds
    t2 = t2 * 1000
    newAudio = AudioSegment.from_wav("oldSong.wav")
    newAudio = newAudio[t1:t2]
    newAudio.export('newSong.wav', format="wav")

我使用 R 进行了类似的操作，如下所示：

library(dplyr)
library(tidyr)
library(reticulate)
use_python('/usr/bin/python3',required = TRUE)
py_config()
pydub.py <- import('pydub')
time.start <- as.numeric(data.df.st02[loop,'time_start'])*1000
time.end <- as.numeric(data.df.st02[loop,'time_end'])*1000
new.audio <- pydub.py$AudioSegment$from_wav('142533.wav')

但返回以下错误：

> new.audio[1:2]
 Error in py_call_impl(callable, dots$args, dots$keywords) : 
  TypeError: can only concatenate list (not "int") to list

谁能启发我如何用[t1:t2]R 编写代码？

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1 回答 1

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python 子集运算符是__getitem__方法:的包装器，是创建slice对象的包装器。您必须导入builtins模块。尝试这个：

require(reticulate)
use_python('/usr/bin/python3',required = TRUE)
pydub.py <- import('pydub', convert=FALSE)
pybuiltins <- import_builtins(convert=FALSE)
new.audio <- pydub.py$AudioSegment$from_wav('142533.wav')
#important: time.start and time.end must be integer
time.start <- as.integer(1*1000)
time.end <- as.integer(2*1000)
#create a slice object
sl<-pybuiltins$slice(time.start,time.end)
new.audio_split<-new.audio$`__getitem__`(sl)
new.audio_split
#<pydub.audio_segment.AudioSegment>
于 2019-03-29T16:03:53.647 回答