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我正在尝试从受 Kerberos 保护的 SDC API 中检索数据。最初，我将凭据发布到 SCH 登录页面，然后使用生成的 cookie 访问 SDC rest api。但是，我无法发布凭据。响应代码为 401，因此无法访问 api。

dpm_auth_creds = {"userName":"", "password":"" }
headers = {"Content-Type": "application/json", "X-Requested-By": "SDC"}
auth_request  = requests.post("https://url:18641/sch/security/users" , data=json.dumps(dpm_auth_creds), headers=headers, verify="file.pem")
cookies = auth_request.cookies
print(auth_request.status_code)
print(auth_request.headers)
url = requests.get("https://url:18641/jobrunner/rest/v1/sdcs", cookies=cookies)
print(url.text)

响应代码为 401：对于 auth_request.status_code

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1 回答 1

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这是来自 Control Hub 中的 REST API 页面：

# login to Control Hub security app
curl -X POST -d '{"userName":"DPMUserID", "password": "DPMUserPassword"}' https://cloud.streamsets.com/security/public-rest/v1/authentication/login --header "Content-Type:application/json" --header "X-Requested-By:SCH" -c cookie.txt

# generate auth token from security app
sessionToken=$(cat cookie.txt | grep SSO | rev | grep -o '^\S*' | rev)
echo "Generated session token : $sessionToken"

# Call SDC REST APIs using auth token
curl -X GET https://cloud.streamsets.com/security/rest/v1/currentUser --header "Content-Type:application/json" --header "X-Requested-By:SCH" --header "X-SS-REST-CALL:true" --header "X-SS-User-Auth-Token:$sessionToken" -i

所以你的 Python 代码应该更像：

dpm_auth_creds = {"userName":"", "password":"" }
headers = {"Content-Type": "application/json", "X-Requested-By": "SDC"}
auth_request  = requests.post("https://url:18641/security/public-rest/v1/authentication/login" , data=json.dumps(dpm_auth_creds), headers=headers, verify="file.pem")
cookies = auth_request.cookies
print(auth_request.status_code)
print(auth_request.headers)
# Need to pass value of SS-SSO-LOGIN cookie as X-SS-User-Auth-Token header
headers = {
  "Content-Type":"application/json",
  "X-Requested-By":"SCH",
  "X-SS-REST-CALL":"true",
  "X-SS-User-Auth-Token":auth_request.cookies['SS-SSO-LOGIN']
}
url = requests.get("https://url:18641/jobrunner/rest/v1/sdcs", headers=headers)
print(url.text)
于 2019-03-29T17:00:36.710 回答