1

我需要将 UNIX 时间戳转换为ByteArrayKotlin 中的 a。问题是,当我使用下面的代码执行此操作时,我得到的结果类似于C1F38E05(hex),它远高于当前纪元时间。

internal fun Int.toByteArray(): ByteArray {
    return byteArrayOf(
            this.ushr(24).toByte(),
            this.ushr(16).toByte(),
            this.ushr(8).toByte(),
            this.toByte()
    )
}

val timeUTC = System.currentTimeMillis().toInt().toByteArray()

正确的方法是什么?

4

2 回答 2

1

如果需要 32 位值,则需要将时间转换为秒。

fun Int.toByteArray() = byteArrayOf(
    this.toByte(),
    (this ushr 8).toByte(),
    (this ushr 16).toByte(),
    (this ushr 24).toByte()
)

val timeUTC = (System.currentTimeMillis() / 1000).toInt().toByteArray()
于 2019-03-28T19:41:46.787 回答
0

System.currentTimeMillis()返回一个Long所以toByteArray必须Long像这样实现:

fun Long.toByteArray(): ByteArray {                     
    val result = ByteArray(8)                           
    result[7] = (this and 0xFF).toByte()                
    result[6] = ((this ushr 8) and 0xFF).toByte()       
    result[5] = ((this ushr 16) and 0xFF).toByte()      
    result[4] = ((this ushr 24) and 0xFF).toByte()      
    result[3] = ((this ushr 32) and 0xFF).toByte()      
    result[2] = ((this ushr 40) and 0xFF).toByte()      
    result[1] = ((this ushr 48) and 0xFF).toByte()      
    result[0] = ((this ushr 56) and 0xFF).toByte()      
    return result                                       
}    

如果您需要这个用于无符号字节,请使用:

fun Long.toByteArray(): UByteArray {
    val result = UByteArray(8)
    result[7] = (this and 0xFF).toUByte()
    result[6] = ((this ushr 8) and 0xFF).toUByte()
    result[5] = ((this ushr 16) and 0xFF).toUByte()
    result[4] = ((this ushr 24) and 0xFF).toUByte()
    result[3] = ((this ushr 32) and 0xFF).toUByte()
    result[2] = ((this ushr 40) and 0xFF).toUByte()
    result[1] = ((this ushr 48) and 0xFF).toUByte()
    result[0] = ((this ushr 56) and 0xFF).toUByte()
    return result
}

这可以像下面的例子一样使用:

fun main() {
    val timeUTC = System.currentTimeMillis().toByteArray()    
    println(timeUTC.map { byte -> byte.toString(16).toUpperCase() }.joinToString(""))
}
于 2019-03-28T06:24:37.993 回答