我不熟悉使用 AWS 开发工具包和构建 API。但是,我正在尝试找到一种构建应用程序的方法,如果我单击 Web 浏览器上的按钮,我希望它触发 amazon sdk Go 功能来构建 AMI。我该怎么办?
我用 Go 浏览了这个关于 RESTful API 的教程。但是,我对 Amazon SDK GO 功能如何与 API 一起使用感到困惑。所以我有类似下面的代码。我只是不知道我在高层次上是否正确地做到了这一点。
package main
import (
"github.com/aws/aws-sdk-go/aws"
"github.com/aws/aws-sdk-go/aws/session"
"github.com/aws/aws-sdk-go/service/ec2"
"github.com/gorilla/mux"
"net/http"
)
func (c *EC2) CreateLaunchTemplate(input *CreateLaunchTemplateInput) (*CreateLaunchTemplateOutput, error) {
// w.Header().Set("Content-Type", "application/json")
svc := ec2.New(session.New())
input := &ec2.CreateLaunchTemplateInput{
LaunchTemplateData: &ec2.RequestLaunchTemplateData{
ImageId: aws.String("ami-0cc142296677e2132"),
InstanceType: aws.String("t2.micro"),
NetworkInterfaces: []*ec2.LaunchTemplateInstanceNetworkInterfaceSpecificationRequest{
{
AssociatePublicIpAddress: aws.Bool(true),
DeviceIndex: aws.Int64(0),
Ipv6AddressCount: aws.Int64(1),
SubnetId: aws.String("subnet-03a04de08c5c6cb8e"),
},
},
TagSpecifications: []*ec2.LaunchTemplateTagSpecificationRequest{
{
ResourceType: aws.String("instance"),
Tags: []*ec2.Tag{
{
Key: aws.String("Name"),
Value: aws.String("webserver"),
},
},
},
},
},
LaunchTemplateName: aws.String("my-template"),
VersionDescription: aws.String("WebVersion1"),
}
result, err := svc.CreateLaunchTemplate(input)
if err != nil {
if aerr, ok := err.(awserr.Error); ok {
switch aerr.Code() {
default:
fmt.Println(aerr.Error())
}
} else {
// Print the error, cast err to awserr.Error to get the Code and
// Message from an error.
fmt.Println(err.Error())
}
return
}
}
func main() {
// Init Router
r := mux.NewRouter()
// Route Handlers / Endpoints
r.HandleFunc("/api/create_ami", CreateLaunchTemplate).Methods("GET")
log.Fatal(http.ListenAndServe(":8000", r))
}