下面是我对新的基于 Spring 3 注释的控制器的设置：
// 调度程序-servlet.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop-3.0.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd">
<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping"/>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver"
p:prefix="/WEB-INF/jsp/"
p:suffix=".jsp" />
<!--
The index controller.
-->
<bean name="indexController"
class="org.springframework.web.servlet.mvc.ParameterizableViewController"
p:viewName="index" />
<!-- Enables plain controllers -->
<bean class="org.springframework.web.servlet.mvc.SimpleControllerHandlerAdapter" />
<bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver">
<property name="order" value="1" />
<property name="ignoreAcceptHeader" value="true" />
<property name="mediaTypes">
<map>
<entry key="xml" value="application/xml" />
<entry key="json" value="application/json" />
</map>
</property>
</bean>
<!-- Entity Property binding for webBindingInitializer -->
<bean class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
<property name="webBindingInitializer">
<bean class="org.opevel.web.BindingInitializer" />
</property>
</bean>
<context:component-scan base-package="org.opevel.web"/>
</beans>
// web.xml
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
<url-pattern>/auth</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
</web-app>
// 弹簧控制器
package org.opevel.web;
@Controller
public class LoginGoogleController {
private static final Logger log = Logger.getLogger(LoginGoogleController.class.getName());
public LoginGoogleController() {
log.info("constructing LoginGoogleController");
}
@RequestMapping(value="/auth", method=RequestMethod.GET)
public String doGet(HttpServletRequest request, HttpServletResponse response) throws Exception {
return "redirect:index";
}
}
当我导航到 /auth 时，我得到一个 404。当我尝试applicationContext像这样注册 bean 时：
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="/auth">GoogleLoginService</prop>
</props>
</property>
<bean id="GoogleLoginService" class="org.opevel.web.LoginGoogleController" />
我得到一个BeanException说明 bean 已经在/logingooglethrough注册ControllerClassNamehandlerMapping。我在 Google App Engine 上使用 Spring 3.0.2。
将不胜感激一些帮助。