-1

我应该如何指定我的 if-else-elif 语句以不让它们在第一个 if 子句之后完成检查条件？

import random
x = random.randint(1, 100)
correct_answer = False
guess_count = 0
answer = input("Try to guess a number in range of 1 to 100... ")
while guess_count < 6 and correct_answer == False:
    if answer != x:
        answer = input("Try again...")
        guess_count = guess_count + 1
    elif answer > x:
        print("Try lower number")
        guess_count = guess_count + 1
    elif answer < x:
        print("Try higher number")
        guess_count = guess_count + 1
    elif answer == x:
        print("You won!")
        correct_answer = True
    elif guess_count > 6:
        print("You ran out of chances, sorry")
        break
4

4 回答 4

1

您可以通过更改条件的顺序来使这更容易，这样您只有在处理完所有退出条件（即赢或输）后才可以要求另一个数字：

import random
x = random.randint(1, 100)
correct_answer = False
guess_count = 0
answer = input("Try to guess a number in range of 1 to 100... ")
while True:
    guess_count = guess_count + 1
    answer = int(answer)
    if answer == x:
        print("You won!")
        correct_answer == True
        break
    if guess_count > 6:
        print("You ran out of chances, sorry")
        break
    if answer > x:
        answer = input("Try a lower number:")
    else:
        answer = input("Try a higher number:")
于 2019-03-21T23:28:48.057 回答
0

我相信这是你真正想要的。我删除了重复的代码并修改了@fozoro 代码，修复了过程中的错误

import random

x = random.randint(1, 100)
correct_answer = False
answer = int(input("Try to guess a number in range of 1 to 100...: "))
guess_count = 1

while guess_count < 6 and correct_answer == False:
    guess_count = guess_count + 1

    if answer != x:
        answer = int(input("Try again...: "))

    if answer > x:
        print("Try lower number")

    if answer < x:
        print("Try higher number")

    if answer == x:
        print("You won!")
        correct_answer = True

    if guess_count >= 6:
        print("You ran out of chances, sorry")
于 2019-03-21T23:25:49.973 回答
0

完整的工作代码：

import random
x = random.randint(1, 100)
correct_answer = False
guess_count = 0
answer = int(input("Try to guess a number in range of 1 to 100... "))
while guess_count < 6 and correct_answer == False:
    if answer != x and answer > x:
        answer = int(input("Try again... The number should be lower "))
        guess_count = guess_count + 1
    if answer != x and answer < x:
        answer = int(input("Try again... The number should be higher "))
        guess_count = guess_count + 1
    if answer == x:
        print("You won!")
        correct_answer = True
    if guess_count > 5:
        print("You ran out of chances, sorry")
        break
于 2019-03-21T23:29:19.157 回答
0

您应该将这些elif语句替换为如下语句if：

import random
x = random.randint(1, 100)
correct_answer = False
guess_count = 0
answer = int(input("Try to guess a number in range of 1 to 100... "))
while guess_count < 6 and correct_answer == False:
    if answer != x:
        answer = int(input("Try again..."))
        guess_count = guess_count + 1
    if answer > x:
        print("Try lower number")
        guess_count = guess_count + 1
    if answer < x:
        print("Try higher number")
        guess_count = guess_count + 1
    if answer == x:
        print("You won!")
        correct_answer = True
    if guess_count > 6:
        print("You ran out of chances, sorry")
        break
于 2019-03-21T23:07:20.847 回答