第一次尝试 PySimpleGui,想要创建一个 exec 程序,允许用户将目录/文件移动或复制到他们选择的目的地,但并不真正了解如何将操作链接到按钮。
我当前的程序如下所示:
import PySimpleGUI as sg
import shutil, errno
src = ""
dest = ""
def copy(src, dest):
try:
shutil.copytree(src, dest)
except OSError as e:
# If the error was caused because the source wasn't a directory
if e.errno == errno.ENOTDIR:
shutil.copy(src, dest)
else:
print('Directory not copied. Error: %s' % e)
#Me testing out commands in PSG
layout = [[ sg.Text("Select path from source to
destination")],
[sg.Text("Source Folder", size=(15,1)), sg.InputText(src),
sg.FolderBrowse()],
[sg.Text("Destination Folder", size=(15,1)),
sg.InputText(dest), sg.FolderBrowse()],
[sg.Button("Transfer", button_color=("white", "blue"), size=
(6, 1)),sg.Button(copy, "Copy", button_color=("white",
"green"), size=(6, 1)),sg.Exit(button_color=("white", "red"),
size=(6, 1))]]
event = sg.Window("Mass File Transfer").Layout(layout).Read()
据我所知,我认为将复制命令包含在按钮的属性中会将其链接到代码中前面定义的命令。我将 src 和 dest 空白作为 src 和 dest 的输入,并添加了浏览文件夹扩展名,以便于文件管理。