嗨，有什么方法可以使用 requests-HTML 获取标签的所有父元素？
例如：
<!DOCTYPE html>
<html lang="en">
<body id="two">
<h1 class="text-primary">hello there</h1>
<p>one two tree<b>four</b>five</p>
</body>
</html>
我想获取b标签的所有父级：[html, body, p]
或者对于h1标签得到这个结果：[html, body]
与优秀lxml：
from lxml import etree
html = """<!DOCTYPE html>
<html lang="en">
<body id="two">
<h1 class="text-primary">hello there</h1>
<p>one two tree<b>four</b>five</p>
</body>
</html> """
tree = etree.HTML(html)
# We search the first <b> element
b_elt = tree.xpath('//b')[0]
print(b_elt.text)
# -> "four"
# Walking around ancestors of this <b> element
ancestors_tags = [elt.tag for elt in b_elt.iterancestors()]
print(ancestors_tags)
# -> [p, body, html]
您可以通过 Element具有elementiterancestors()
您可以这样做：
from requests_html import HTML
html = """<!DOCTYPE html>
<html lang="en">
<body id="two">
<h1 class="text-primary">hello there</h1>
<p>one two tree<b>four</b>five</p>
</body>
</html>"""
html = HTML(html=html)
b = html.find('b', first=True)
parents = [a for a in b.element.iterancestors()]