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我需要一些帮助才能使 DIGEST Authentication 正常工作。我正在使用 apache 4.1 库。当我尝试登录时，我得到了。

线程“主”javax.net.ssl.SSLPeerUnverifiedException 中的异常：对等体未通过身份验证

我正在尝试登录 Asterisk SwitchVox Dev Extend API，您只需发送一个 xml 帖子，它就会返回信息。我当然有正确的用户名/密码，并且我在 PERL 脚本上得到了这个，但我无法在 JAVA 中得到它。

这是我的代码

public class Main {

public static void main(String[] args) throws Exception {

    HttpHost targetHost = new HttpHost("192.168.143.253", 443, "https");

    DefaultHttpClient httpclient = new DefaultHttpClient();
    try {
        httpclient.getCredentialsProvider().setCredentials(
                new AuthScope("192.168.143.253", targetHost.getPort()),
                new UsernamePasswordCredentials("username", "mypassword"));

        // Create AuthCache instance
        AuthCache authCache = new BasicAuthCache();
        // Generate DIGEST scheme object, initialize it and add it to the local auth cache

        DigestScheme digestAuth = new DigestScheme();

        authCache.put(targetHost, digestAuth);

        // Add AuthCache to the execution context
        BasicHttpContext localcontext = new BasicHttpContext();
        localcontext.setAttribute(ClientContext.AUTH_CACHE, authCache);

        HttpGet httpget = new HttpGet("https://192.168.143.253/xml/");

        System.out.println("executing request: " + httpget.getRequestLine());
        System.out.println("to target: " + targetHost);

        for (int i = 0; i < 3; i++) {
            HttpResponse response = httpclient.execute(targetHost, httpget, localcontext);
            HttpEntity entity = response.getEntity();

            System.out.println("----------------------------------------");
            System.out.println(response.getStatusLine());
            if (entity != null) {
                System.out.println("Response content length: " + entity.getContentLength());
            }
            EntityUtils.consume(entity);
        }

    } finally {
        // When HttpClient instance is no longer needed,
        // shut down the connection manager to ensure
        // immediate deallocation of all system resources
        httpclient.getConnectionManager().shutdown();
    }
}

}

4

1 回答 1

3

我终于找到了我的问题的答案。

public static void main(String args[]) {

    final String username = "user";
    final String password = "password";



    Authenticator.setDefault(new Authenticator() {
        @Override
          protected PasswordAuthentication getPasswordAuthentication() {
                PasswordAuthentication pa = new PasswordAuthentication (username, password.toCharArray());
                //System.out.println(pa.getUserName() + ":" + new String(pa.getPassword()));
                return pa;
            }
          });
    BufferedReader in = null;
    StringBuffer sb = new StringBuffer();

    try {
        //URL url = new URL(strURL);

        HttpsURLConnection connection = (HttpsURLConnection) new URL("https://secureHost/").openConnection();
                    connection.setDefaultHostnameVerifier(new CustomizedHostnameVerifier());
                    connection.setHostnameVerifier(new CustomizedHostnameVerifier());
                    connection.setDoOutput(true);
                    connection.setDoInput(true);
                    connection.setRequestMethod("POST");
                    connection.setRequestProperty("Content-Type","text/xml");
                    PrintWriter out = new PrintWriter(connection.getOutputStream());
                    String requestString = "<request method=\"switchvox.currentCalls.getList\"></request>";

                    out.println(requestString);
                    out.close();

        in = new BufferedReader(new InputStreamReader(connection
                .getInputStream()));

        String line;

        while ((line = in.readLine()) != null) {
            sb.append(line).append("\n");
        }
    } catch (java.net.ProtocolException e) {
        sb.append("User Or Password is wrong!");
        e.printStackTrace();
    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        try {
            if (in != null) {
                in.close();
            }
        } catch (Exception e) {
            System.out.println("Exception");
        }
    }

    System.out.println("The Data is: " + sb.toString());

}

}

于 2011-04-04T02:10:51.353 回答