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我有一个居民，但似乎无法获得该居民所属的 SSA 集。我试过res.ssa_set.all() .ssas_set.all()和.ssa_resident_set.all()。好像管不了 通过另一个表进行反向 m2m 查找的语法是什么？

编辑：我收到“QuerySet as no attribute”错误。嗯？

class SSA(models.Model):
    name = models.CharField(max_length=100)
    cost_center = models.IntegerField(max_length=4)
    street_num = models.CharField(max_length=9)
    street_name = models.CharField(max_length=40)
    suburb = models.CharField(max_length=40)
    post_code = models.IntegerField(max_length=4, blank=True, null=True)

    def __unicode__(self):
        return self.name

class Resident(models.Model):
    cris_id = models.CharField(max_length=10, primary_key=True)
    first_name = models.CharField(max_length=20)
    last_name = models.CharField(max_length=20)
    ssas = models.ManyToManyField('SSA', through='SSA_Resident', verbose_name="SSAs")

    def __unicode__(self):
        return self._get_full_name()

    def _get_full_name(self):
        return u"%s %s" %(self.first_name, self.last_name)

    full_name = property(_get_full_name)

class SSA_Resident(models.Model):
    id = models.AutoField(primary_key=True)
    resident = models.ForeignKey('Resident')
    ssa = models.ForeignKey('SSA', verbose_name="SSA")
    active = models.BooleanField(default=True)
    def __unicode__(self):
        return u"%s - %s" %(self.resident.full_name, self.ssa.name)
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1 回答 1

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我试图评估一个查询集对象，而不是对象本身。在查询集上执行 get 然后查找关系集工作正常。我正在更改为社区 wiki，并将其留在这里，以防其他人像我一样愚蠢。

一个工作示例：

resident = Resident.objects.filter(name='Johnny')
resident.ssa_set.all() # fail
resident = resident.get() # will fail if more than one returned by filter
resident.ssa_set.all() # works, since we're operating on an instance, not a queryset
于 2009-02-15T04:07:41.013 回答