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我有一个下表，其中有员工的交易，其中工资为代码“S”：

Id | Code | Amount  | Date
1  | B    | 40      | 2017-01-01
1  | S    | 45000   | 2017-01-02
1  | D    | 30000   | 2017-01-15
1  | B    | 15000   | 2017-01-20
1  | S    | 45000   | 2017-02-02
1  | B    | -20000  | 2017-02-04
1  | B    | -10000  | 2017-02-05

我的目标是查看员工需要多少天才能耗尽所有薪水

这是我想要的输出：

Id | Code | Amount | Month | # days when all salary drains
1  | S    | 45000  | 01    | 20
1  | S    | 45000  | 01    | 0

我已经按照这个并尝试了以下 SQL 查询：

with cte as
     (
       select *,
        --CASE WHEN Transaction_Code in ('521', '522') then Transaction_Amt else null end as Last_V_ID
          -- find the latest 'V' ID per ArtNo
          max(case when Transaction_Code in ('521', '522') then Transaction_Amt end) 
          over (partition by INTERNAL_ACCT_NUM order by value_date) as Last_V_ID
       from [10.16.42.25].[Cross_Sell_PL].[dbo].[PL_NONPL_TRANS]
    WHERE INTERNAL_ACCT_NUM = '0103PBS8T6001'
    --order by value_date
     )
    select *,
     case when Transaction_Code in ('521', '522') then Transaction_Amt else
      ( lag(Last_V_ID,1,0) OVER (PARTITION BY INTERNAL_ACCT_NUM ORDER BY VALUE_DATE) ) 
      + Transaction_Amt end as running_balance,

       sum(case when Transaction_Amt < Last_V_ID then null else Transaction_Amt end)
       over (partition by INTERNAL_ACCT_NUM order by VALUE_DATE rows unbounded preceding)
    from cte
    order by Internal_Acct_num, value_date

问题是我无法限制代码之间的计算，也无法计算天数。

4

1 回答 1

1

根据您的反馈修改了我的答案。

该查询现在使用公用表表达式为工资金额和每月支付日期构建派生表，然后是另一个派生表，该表编译每个日历月汇总的所有事务的列表。

每月交易的总和与工资金额进行比较，只有当金额超过工资阈值时才会显示总天数（包括+1，因为这包括作为第 1 天支付工资的日期）。

这样的查询显示 3 行，因为提供的示例数据包括 12 月的工资月份，但是没有与 12 月相比的工资金额，因此额外的 0。我希望这会有所帮助。

declare @employee_transaction table (
    Id int,
    Code nvarchar(1),
    Amount int,
    Date Date
);

insert into @employee_transaction (id, Code, Amount, Date)
values
(1  , 'B'    , 40      , '2017-01-01'),
(1  , 'S'    , 45000   , '2017-01-02'),
(1  , 'D'    , 30000   , '2017-01-15'),
(1  , 'B'    , 15000   , '2017-01-20'),
(1  , 'S'    , 45000   , '2017-02-02'),
(1  , 'B'    , -20000  , '2017-02-04'),
(1  , 'B'    , -10000  , '2017-02-05');


with Salaries as (Select INTERNAL_ACCT_NUM, Transaction_Code, Value_Date, 
Transaction_Amt as Salary_Per_Month from #test1 e where 
Transaction_Code='S'), 
Deductions as (select sum(case when Transaction_Amt<0 then Transaction_Amt 
else 0 end) as Amount, Max(Value_Date) as Drain_date from #TEST1 e2 
where Transaction_Code <>'S' and Value_Date>(select Value_Date from #TEST1 
e3 where Transaction_Code='S' and 
DATEPART(month,e2.Value_Date)=DATEPART(month,e3.Value_Date) 
and e3.Internal_Acct_Num=e2.Internal_Acct_Num) 
group by DATEPART(month,e2.Value_Date)) 

select distinct s.INTERNAL_ACCT_NUM, s.Transaction_Code, s.Salary_Per_Month, 
DATEPART(Month,e.Value_Date) as Month, 
coalesce(DATEDIFF(Day,S.Value_Date,(select d.Drain_Date from Deductions d 
where d.Amount+S.Salary_Per_Month<=0 and 
DatePart(month,d.Drain_Date)=DatePart(month,e.Value_Date) and 
d.drain_date>=s.value_date))+1,0) 
from #TEST1 e 
inner join Salaries s on e.Transaction_Code=s.Transaction_Code 
and e.INTERNAL_ACCT_NUM=s.INTERNAL_ACCT_NUM and s.Value_Date>=e.Value_Date 
and DATEPART(month, s.Value_Date)=DATEPART(month, e.Value_Date) 
order by Month;
于 2019-03-01T14:26:33.863 回答