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我有这个服务器代码，我使用'add_url_rule'来添加一个视图函数。

        app = connexion.App(__name__, specification_dir='./swagger/')
        app.add_url_rule('/etsiproxy/notify/<vnf_id>',
                        view_func=handle_sol003_notifications,
                        methods=['GET', 'POST'])

        app.server = 'tornado'

        # This is run from a different thread, create a default event loop for
        # this thread for tornado.
        loop = asyncio.new_event_loop()
        asyncio.set_event_loop(loop)

        self.threadLoop = loop

        # Flask with Tornado works in single thread. Use the thread to store
        # the server object, so that it can be accessed from the handler
        thr = threading.current_thread()
        thr.api_provider = self

        app.run(server='tornado', port=self._port, host=self._host, debug=False)

这是我的处理函数：

def handle_sol003_notifications(cls, vnf_id):
    notification = connexion.request.get_json()

    if connexion.request.method == 'GET':
        return None, 204

    if notification['notificationType'] == 'VnfLcmOperationOccurrenceNotification':
        payload = Sol003Yang.YangInput_Sol003_Sol003Rpc.from_dict(
            {"vnfinstanceid": notification['vnfInstanceId'],
            "notificationstatus": notification['notificationStatus'],
            "operationstate": notification['operationState'],
            "operation": notification['operation'],
            "vnflcmopoccid": notification['vnfLcmOpOccId'],
            })

        task = get_api_provider().run_in_tasklet_loop(cls.DTS.query_rpc("I,/sol003:sol003-rpc", 0, payload))


    return None, 204

当在这个 url 上点击一个 post 请求时，我会得到这个错误： TypeError: the view function did not return a valid response。这是因为我返回 None，而烧瓶不喜欢这样。

但是如果我使用return '', 204，它会给出另一个错误，说不能用 204 发送正文。

在这种情况下，我怎样才能返回 204 no content？

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