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使用 simple_salesforce 连接器,我的查询返回了 c.150k 记录,以下将数据读入数据帧的方法花费了很长时间,以至于我刚刚进入 SF,运行报告,下载它并将其读取给 pandas。有更快的方法吗?谢谢

import pandas as pd
from simple_salesforce import Salesforce

fields = ['field' + str(i) for i in range(1, 10)]
fields_str = ", ".join(fields)
query_str = "select {} from account".format(fields_str)

sf = Salesforce(username= myusername, password= mypwd, security_token = mytoken)
df = sf.query_all(query_str)

sf_df = pd.DataFrame(columns = fields)

for account in range(df['totalSize']):
     account_dict = {}
     for field in fields:
         account_dict[field] = df['records'][account][field]
     dict_df = pd.DataFrame.from_dict([account_dict])
     sf_df = sf_df.append(dict_df, sort=False)
     del(account_dict)
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1 回答 1

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您可以使用 ['records'] 键直接提取记录。

df = sf.query_all('SELECT ID, CreatedDate FROM Account LIMIT 10')['records']
df = pd.DataFrame(df)
df

或作为单个代码行:

df = pd.DataFrame(sf.query_all('SELECT ID, Createddate FROM Account LIMIT 10')['records'])
df

如果该attributes列不包含您要查看的数据,您可以使用.drop(columns=['attributes']将其从返回的数据框中删除。

df = sf.query_all('SELECT ID, CreatedDate FROM Account LIMIT 10')['records']
df = pd.DataFrame(df)
df.drop(columns=['attributes'],inplace=True)
df

或作为单个代码行:

df = pd.DataFrame(sf.query_all('SELECT ID, Createddate FROM Account LIMIT 10')['records']).drop(columns=['attributes'])
df
于 2019-03-01T20:43:05.253 回答