只要您的代码是正确的,假设这没有问题。这是一个示例和日志。
option notes;
%let size=1000;
/*Create a table for reference*/
DATA input_data;
ARRAY var_[*] var_1-var_&size.;
DO i = 1 to &size.;
DO j = 1 to &size.;
var_(j)= i*j;
END;
output;
END;
RUN;
/*Log, square, cubic, logit transform all variables*/
DATA input_transform;
SET input_data;
ARRAY _var[*] var_1-var_&size.;
ARRAY _log[*] log_1-log_&size.;
ARRAY _logit[*] logit_1-logit_&size.;
ARRAY _sq[*] sq_1-sq_&size.;
ARRAY _cubic[*] cubic_1-cubic_&size.;
DO i = 1 to &size.;
_log(i) = log(_var(i));
_logit(i) = sqrt(_var(i));
_sq(i) = _var(i)**2;
_cubic(i) = _var(i)**3;
END;
RUN;
和日志:
1576 option notes;
1577 %let size=1000;
1578
1579 /*Create a table for reference*/
1580 DATA input_data;
1581 ARRAY var_[*] var_1-var_&size.;
1582
1583 DO i = 1 to &size.;
1584 DO j = 1 to &size.;
1585 var_(j)= i*j;
1586 END;
1587 output;
1588 END;
1589 RUN;
NOTE: The data set WORK.INPUT_DATA has 1000 observations and 1002
variables.
NOTE: DATA statement used (Total process time):
real time 0.03 seconds
cpu time 0.03 seconds
1590
1591 /*Log, square, cubic, logit transform all variables*/
1592 DATA input_transform;
1593 SET input_data;
1594 ARRAY _var[*] var_1-var_&size.;
1595 ARRAY _log[*] log_1-log_&size.;
1596 ARRAY _logit[*] logit_1-logit_&size.;
1597 ARRAY _sq[*] sq_1-sq_&size.;
1598 ARRAY _cubic[*] cubic_1-cubic_&size.;
1599
1600 DO i = 1 to &size.;
1601 _log(i) = log(_var(i));
1602 _logit(i) = sqrt(_var(i));
1603 _sq(i) = _var(i)**2;
1604 _cubic(i) = _var(i)**3;
1605 END;
1606 RUN;
NOTE: There were 1000 observations read from the data set
WORK.INPUT_DATA.
NOTE: The data set WORK.INPUT_TRANSFORM has 1000 observations and 5002
variables.
NOTE: DATA statement used (Total process time):
real time 0.12 seconds
cpu time 0.10 seconds