3

我有一个问题是我的RestTemplate.postForEntity(url, restRequest, RepoResponse.class)呼叫失败，因为它无法反序列化表单的日期：

  • 2019-02-01T12:00:00.000-0500

因为时区中缺少冒号。

根据这个答案，看起来我想更改我的日期RestTemplate格式ObjectMapper。

我在这里尝试了一个解决方案： https ://stackoverflow.com/a/38286322/14250

这给了我以下代码：

restTemplate = new RestTemplate();
ObjectMapper objectMapper = new ObjectMapper();
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS[XXX][X]");
objectMapper.setDateFormat(format);

MappingJackson2HttpMessageConverter messageConverter = new MappingJackson2HttpMessageConverter();
messageConverter.setPrettyPrint(false);
messageConverter.setObjectMapper(objectMapper);
restTemplate.getMessageConverters().removeIf(m->m.getClass().getName().equals(MappingJackson2HttpMessageConverter.class.getName()));
restTemplate.getMessageConverters().add(messageConverter);

不幸的是，我收到以下错误

com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `java.time.OffsetDateTime` (no Creators, like default construct, exist): no String-argument constructor/factory method to deserialize from String value ('2019-02-13T12:33:19.179-0500')

有没有一种简单的方法可以让 RestTemplate 支持上述日期时间格式？

4

1 回答 1

1

当您使用java.time.*类并且Jackson最好从JavaTimeModule来自jackson-datatype-jsr310模块的注册开始。

import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.datatype.jsr310.JavaTimeModule;

import java.time.OffsetDateTime;

public class JsonApp {

    public static void main(String[] args) throws Exception {
        JavaTimeModule javaTimeModule = new JavaTimeModule();

        ObjectMapper mapper = new ObjectMapper();
        mapper.registerModule(javaTimeModule);

        String json = "{\"now\":\"2019-02-01T12:01:01.001-0500\"}";
        System.out.println(mapper.readValue(json, Time.class));
    }
}

class Time {

    @JsonFormat(pattern = "uuuu-MM-dd'T'HH:mm:ss.SSSX")
    private OffsetDateTime now = OffsetDateTime.now();

    public OffsetDateTime getNow() {
        return now;
    }

    public void setNow(OffsetDateTime now) {
        this.now = now;
    }

    @Override
    public String toString() {
        return "PrintObject{" +
                "now=" + now +
                '}';
    }
}

上面的代码打印：

PrintObject{now=2019-02-01T17:01:01.001Z}
于 2019-02-24T23:27:53.377 回答