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我正在尝试在为特征实现生成签名的宏中索引数据元组,但有一些错误。我可以索引元组还是需要其他解决方案?破解tuple_index我在谷歌找到的,但它对我不起作用。

https://play.rust-lang.org/?version=stable&mode=debug&edition=2018&gist=7d4bc0f56c643cf4693279a9bd9db973

macro_rules! expr { ($x:expr) => ($x) } // HACK
macro_rules! tuple_index {
    ($tuple:expr, $idx:tt) => { expr!($tuple.$idx) }
}
macro_rules! gen_packer {
    (@step $data: expr, $_idx:expr,) => {};

    (@step $data: expr, $idx:expr, $T:ident, $($tail:ident,)*) => {
        // out.append(&mut $T::pack(tuple_index!(data,$idx)));
        tuple_index!($data, $idx);

        gen_packer!(@step $data, $idx + 1, $($tail,)*);
    };

    ($($T:ident),*) => {
        impl<$($T,)+> Packer<($($T,)+)> for Iproto
        where $($T: Pack<$T>,)+
        {
            fn pack(self, data: ($($T,)+)) -> Vec<u8> {
                let mut out = vec![];
                gen_packer!(@step data, 0, $($T,)*);
                return out
            }
        }
    }
}

gen_packer!(A);

编译错误:

error: unexpected token: `0`
--> src/lib/iproto.rs:70:29
   |
70 |         tuple_index!($data, $idx);
   |                             ^^^^
...
99 | gen_packer!(A);
   | --------------- in this macro invocation

error: unexpected token: `,`
  --> src/lib/iproto.rs:63:46
   |
63 |     ($tuple:expr, $idx:tt) => { expr!($tuple.$idx) }
   |                                              ^
...
99 | gen_packer!(A);
   | --------------- in this macro invocation

error: no rules expected the token `0`
  --> src/lib/iproto.rs:70:29
   |
61 | macro_rules! expr { ($x:expr) => ($x) } // HACK
   | ----------------- when calling this macro
...
70 |         tuple_index!($data, $idx);
   |                             ^^^^ no rules expected this token in macro call
...
99 | gen_packer!(A);
   | --------------- in this macro invocation

error: aborting due to 3 previous errors
4

1 回答 1

1

我可以索引元组还是需要其他解决方案?

不会。表达式$idx + 1将产生不同的标记,例如0, +, 1,并且无法将其计算为声明性宏中的单个文字标记。

于 2019-02-13T10:21:04.773 回答