74

使用 @types/react 16.8.2 和 TypeScript 3.3.1。

我直接从React 文档中提取了这个 forward refs 示例,并添加了几个类型参数:

const FancyButton = React.forwardRef<HTMLButtonElement>((props, ref) => (
  <button ref={ref} className="FancyButton">
    {props.children}
  </button>
));

// You can now get a ref directly to the DOM button:
const ref = React.createRef<HTMLButtonElement>();
<FancyButton ref={ref}>Click me!</FancyButton>;

我在下面的最后一行收到以下错误FancyButton

类型“ { children: string; ref: RefObject<HTMLButtonElement>; }”不可分配给类型“ IntrinsicAttributes & RefAttributes<HTMLButtonElement>”。类型“ ”.ts(2322)children上不存在属性“ ”IntrinsicAttributes & RefAttributes<HTMLButtonElement>

React.forwardRef 的返回值的类型定义似乎是错误的,没有正确合并 children 道具。如果我<FancyButton>自动关闭,错误就会消失。缺少此错误的搜索结果使我相信我遗漏了一些明显的东西。

4

3 回答 3

104

trevorsg,您需要传递按钮属性:

import * as React from 'react'

type ButtonProps = React.HTMLProps<HTMLButtonElement>

const FancyButton = React.forwardRef<HTMLButtonElement, ButtonProps>((props, ref) => (
  <button type="button" ref={ref} className="FancyButton">
    {props.children}
  </button>
))

// You can now get a ref directly to the DOM button:
const ref = React.createRef<HTMLButtonElement>()

<FancyButton ref={ref}>Click me!</FancyButton>

添加:

在最新版本的 TS 和 @types/react 中,您还可以React.ComponentPropsWithoutRef<'button'>使用React.HTMLProps<HTMLButtonElement>

于 2019-02-13T19:07:34.453 回答
19

aMarCruz 和 euvs 给出的答案都行得通,但它们对消费者有点撒谎。他们说他们接受所有 HTMLButtonElement 道具,但他们忽略它们而不是将它们转发给按钮。如果您只是想正确合并 children 道具,那么您可能想要使用 React.PropsWithChildren 代替:

import React from 'react';

interface FancyButtonProps {
    fooBar?: string; // my custom prop
}

const FancyButton = React.forwardRef<HTMLButtonElement, React.PropsWithChildren<FancyButtonProps>>((props, ref) => (
    <button type="button" ref={ref} className="fancy-button">
        {props.children}
        {props.fooBar}
    </button>
));

FancyButton.displayName = 'FancyButton';

或者显式添加一个 children 道具:

interface FancyButtonProps {
    children?: React.ReactNode;
    fooBar?: string; // my custom prop
}

const FancyButton = React.forwardRef<HTMLButtonElement, FancyButtonProps>((props, ref) => (
    <button type="button" ref={ref} className="fancy-button">
        {props.children}
        {props.fooBar}
    </button>
));

FancyButton.displayName = 'FancyButton';

或者如果你真的想接受所有的按钮道具并转发它们(例如让消费者选择按钮类型=“提交”),那么你可能想要使用休息/传播:

import React from 'react';

interface FancyButtonProps extends React.ComponentPropsWithoutRef<'button'> {
    fooBar?: string; // my custom prop
}

const FancyButton = React.forwardRef<HTMLButtonElement, FancyButtonProps>(
    ({ children, className = '', fooBar, ...buttonProps }, ref) => (
        <button {...buttonProps} className={`fancy-button ${className}`} ref={ref}>
            {children}
            {fooBar}
        </button>
    ),
);

FancyButton.displayName = 'FancyButton';
于 2021-03-30T18:47:22.260 回答
11

aMarCruz 给出的答案效果很好。但是,如果您还需要将自定义道具传递给FancyButton,那么可以这样做。

interface FancyButtonProps extends React.ComponentPropsWithoutRef<'button'> {
    fooBar?: string; // my custom prop
}

const FancyButton = React.forwardRef<HTMLButtonElement, FancyButtonProps>((props, ref) => (
    <button type="button" ref={ref} className="FancyButton">
        {props.children}
        {props.fooBar}
    </button>
));


/// Use later

// You can now get a ref directly to the DOM button:
const ref = React.createRef<HTMLButtonElement>()

<FancyButton ref={ref} fooBar="someValue">Click me!</FancyButton>

只需在此处添加即可完成。

于 2020-12-16T23:54:37.723 回答