我有这个代码:
<div id="busca">
<div id="form_busca">
<%= form_for @search, :url => root_path, :html => {:method => :get} do |f| %>
<%= f.text_field :bairro_or_cidade_or_logradouro_or_estado_contains ,:id => "campo_busca", :placeholder => "Pesquise por logradouro, bairro ou cidade" %>
<%= f.submit "Buscar", :id => "btn_busca" %>
</div>
</div>
<div id="filtros">
<ul>
<li><%= link_to "Some Text", root_path(:search => {:quartos_less_than => 2}) %></li>
<li><%= link_to "Some Text2", params.merge(:search => {:quartos_less_than => 2}) %></li>
<li><%= link_to "1 quarto", root_path(params.merge(:search => params[:search], :filter => {:quartos_less_than => 2})) %></li>
<li><%= link_to "+ de 1 quarto", params.merge(:search => params[:search], :filter => {:quartos_greater_than => 2}) %></li>
<li><%= link_to "1 banheiro", params.merge(:search => params[:search], :filter => {:banheiros_less_than => 2}) %></li>
<li><%= link_to "+ de 1 banheiro", params.merge(:search => params[:search], :filter => {:banheiros_greater_than => 2}) %></li>
</ul>
</div>
<a id="filtros_link" href="#">Filtros »</a>
<% end %>
我想将此链接从filtros(过滤器)合并到以前的搜索。例如:我搜索一个城市,然后过滤这个搜索以显示那些只有 1 个浴室的城市。
有人可以帮助我吗?
我正在使用 ruby 1.8.7 和 Rails 3.0.4。搜索 gem 是 meta_search。
从现在开始谢谢你!!