1

我一直在开发:

public List<DepartmentType> getAllDepartmentTypes() {
    return session.getCurrentSession()
                .createCriteria(DepartmentType.class)
                .addOrder(Order.asc("department_type_name"))
                .list();
}

在哪里:

@Autowired
SessionFactory session;

这个关于替代品的问题中createCriteria(),我创建了一种获取列表的方法:

public List<DepartmentType> getAllDepartmentTypes() {
    CriteriaBuilder builder = session.getCurrentSession().getCriteriaBuilder();
    CriteriaQuery<DepartmentType> criteriaQuery = builder.createQuery(DepartmentType.class);    
    return session.getCurrentSession()
                .createQuery(criteriaQuery)
                .getResultList();
}

但我仍然不知道在哪里使用:

addOrder(Order.asc("department_type_name"))
4

1 回答 1

1

您需要使用CriteriaQuery.orderBy()提供 order by 子句。

public List<DepartmentType> getAllDepartmentTypes() {
    CriteriaBuilder builder = session.getCurrentSession().getCriteriaBuilder();
    CriteriaQuery<DepartmentType> criteriaQuery = builder.createQuery(DepartmentType.class);    
    Root<DepartmentType> deptType = criteriaQuery.from(DepartmentType.class);
    criteriaQuery.select(deptType).orderBy(builder.asc(deptType.get("department_type_name")));
    return session.getCurrentSession()
                .createQuery(criteriaQuery)
                .getResultList();
}
于 2019-02-10T10:09:59.830 回答