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我正在使用 django-viewflow 来跟踪复杂的业务流程。为了避免有长的 Flow 类和 flow.py 文件，我希望将一个流馈送到另一个流。这可能吗？

我尝试了以下代码，但 Python 抛出了 NotImplemented 异常。

class SecondFlow(Flow):
    process_class = SecondProcess
    start = (...)

class FirstFlow(Flow):
    process_class = FirstProcess
    start = (
        flow.Start(
            CreateProcessView,
            fields=['foo']
        ).Next(SecondFlow.start)
    )

如果 FirstFlow 路由到 SecondFlow 的开头，那就太好了。

编辑：我尝试使用提供的建议和文档，但出现以下错误：'StartFunction' object has no attribute 'prepare'

下面是我的新代码。

from viewflow import flow, frontend
from viewflow.base import this, Flow
from viewflow.flow.views import CreateProcessView, UpdateProcessView

from .models import FirstProcess, SecondProcess

@frontend.register
class SecondFlow(Flow):
    process_class = SecondProcess
    start = flow.StartFunction(this.create_flow
            ).Next(this.enter_text)

    def create_flow(self, activation, **kwargs):
        activation.prepare()
        activation.done()

    enter_text = (
        flow.View(
            UpdateProcessView,
            fields=['text']
        ).Next(this.end)
    )

    end = flow.End()


@frontend.register
class FirstFlow(Flow):
    process_class = FirstProcess

    start = (
        flow.Start(
            CreateProcessView,
            fields=['text']
        ).Next(this.initiate_second_flow)
    )

    initiate_second_flow = (
        flow.Handler(this.start_second_flow
        ).Next(this.end)
    )

    def start_second_flow(self, activation):
        SecondFlow.start.run()

    end = flow.End()

第二次编辑：在我将装饰器添加到create_flowSecondFlow 的方法后它可以工作。

from django.utils.decorators import method_decorator
...

@frontend.register
class SecondFlow(Flow):
    process_class = SecondProcess
    start = flow.StartFunction(this.create_flow
            ).Next(this.enter_text)

    @method_decorator(flow.flow_start_func)
    def create_flow(self, activation, **kwargs):
        activation.prepare()
        activation.done()

...
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1 回答 1

1

flow.Start is the task for a Start view that invoked by a user and creates a process. View could have some logic, and usually, that logic relays on a request data. So you can't invoke flow.StartView and flow.View elsewhere except by accessing an URL form a browser.

To activate some process programmatically there is the flow.StartFunction - http://docs.viewflow.io/viewflow_core_node.html#viewflow.nodes.StartFunction

And to execute it from the other flow, flow.Handler could be used - http://docs.viewflow.io/viewflow_core_node.html#viewflow.nodes.Handler

于 2019-02-11T09:09:47.027 回答