照片:id、uid、日期;
好友:uid1、uid2、日期、状态;
我想为用户的朋友展示最新的照片。我该怎么办?
这将做到:
SELECT p.id
FROM Photos AS p, Friends AS f
WHERE p.uid = f.uid2 AND f.uid1 = ${userX.id}
ORDER BY p.date DESC
LIMIT 1;
SELECT id FROM photos WHERE uid IN (SELECT uid2 FROM friends WHERE uid1 = {$uid1} ORDER BY date DESC LIMIT 1);
我认为 UID1 是用户,UID2 是朋友,这将检索所有 ID