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我有两个应用程序。一个 spring-boot web 服务和另一个使用它的服务。我不确定如何处理异常并将它们报告给客户。

公开网络服务的方法：

//web service com springboot
    @PostMapping(value = "/save", produces = {MediaType.APPLICATION_XML_VALUE, MediaType.APPLICATION_JSON_VALUE},
                    consumes = {MediaType.APPLICATION_XML_VALUE, MediaType.APPLICATION_JSON_VALUE})
    public Pessoa save(@RequestBody Pessoa pessoa) {    
        // email field is unique, might throw constraint violation...   
            return pessoaRepository.save(pessoa);               
    }

以及使用它的客户端应用程序（没有 spring，只有 javaEE Client API）：

public Pessoa savePessoa(Pessoa pessoa) {
    Client client = ClientBuilder.newClient();
    WebTarget target = client.target(URL_WS+ "/save");

    Entity<Pessoa> data = Entity.entity(pessoa, MediaType.APPLICATION_XML_TYPE);

    pessoa = target.request(MediaType.APPLICATION_XML_TYPE).post(data, Pessoa.class);

    return pessoa;
}

Pessoa 的 email 字段是唯一的，保存时会触发一些违反约束的异常。如果有异常，我该如何正确地向客户报告？

4

1 回答 1

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创建异常类

public class PessoaException extends RuntimeException { 
   public PessoaException(String exception) {
    super(exception);
      }
    }

更改您的服务代码如下：-

 @PostMapping(value = "/save", produces = {MediaType.APPLICATION_XML_VALUE, MediaType.APPLICATION_JSON_VALUE},
                    consumes = {MediaType.APPLICATION_XML_VALUE, MediaType.APPLICATION_JSON_VALUE})
    public Pessoa save(@RequestBody Pessoa pessoa) {    
        // email field is unique, might throw constraint violation... 
            try{
            Pessoa p = pessoaRepository.save(pessoa);
            }catch(Exception e){
                throw new PessoaException("Message" + e);
            }   
            return p;               
    }
于 2019-01-18T14:53:43.167 回答