我找到了一个解决方案:我将 cell_info 更改为接受一个int channel
参数,以便它返回一个整数而不是一个数组。然后我写了这个:
class img_generator_fn {
public:
using value_type = int;
img_generator_fn(const Map *map, const Position ¢er, shared_ptr<const Player> player,
const unsigned int field_radius)
: m_map(map), m_center(center), m_player(player), m_translation(-(field_radius + 1)) {}
~img_generator_fn() { m_map = nullptr; }
inline auto operator()(const unsigned int x, const unsigned int y, const unsigned int channel) const {
return m_map->at(m_center + Position(x, y))->cell_info(m_player, channel);
}
template <class It> inline auto element(It, It end) const {
return m_map->at(m_center + Position(*(end - 2) + m_translation, (*(end - 3)) + m_translation))
->cell_info(m_player, *(end - 1));
}
private:
const Map *m_map;
const Position &m_center;
shared_ptr<const Player> m_player;
const unsigned int m_translation;
};
template <unsigned int field_side> auto field(const Position ¢er, shared_ptr<const Player> player) const {
const array<unsigned int, 3> shape = {field_side, field_side, 3};
auto gen = xt::detail::make_xgenerator(img_generator_fn(this, center, player, (field_side - 1) / 2), shape);
return xt::xtensor_fixed<int, xt::xshape<field_side, field_side, 3>>(gen);
}
这里Map
表示一个 2D 矩阵,它是包含player
我想要存储在图像中的信息的结构。该函数at
在指定位置拾取地图单元格(地图单元格将转换为像素)。该函数使用 xgeneratorfield
生成以给定地图为中心的图像。center