python - 将 blocktrans 与“with”和“count”关键字一起使用

Question

是否可以同时使用{% blocktrans %}“ with ”和“ count ”？

该文档仅描述了单独的使用：

{% blocktrans with foo|filter as bar and baz|filter as boo %}
{% blocktrans count var|length as count %}

我需要打印一个变量的值，而翻译取决于另一个变量。我尝试了以下代码：

{% blocktrans count cnt as count with cnt|make_text_from_count as text_count %}
    and other {{ text_count }} city
{% plural %}
    and other {{ text_count }} cities
{% endblocktrans %}

它显示text_count变量的值，但不翻译文本。

Python 2.6.6、Django 1.3、django 模板。

Answer 1

对的，这是可能的。您只需要注意blocktrans参数的顺序：with需要紧随其后的局部变量绑定，count并且其各自的变量绑定紧随其后。

文档（至少对于 1.5 版）有几个复数示例。第二个示例（作为“更复杂的示例”介绍）显示了同时使用with和时的顺序count：

{% blocktrans with amount=article.price count years=i.length %}
That will cost $ {{ amount }} per year.
{% plural %}
That will cost $ {{ amount }} per {{ years }} years.
{% endblocktrans %}

如果您不需要除计数器变量之外的任何其他变量，则根本不要使用关键字with。这显示在记录在案的第一个示例中，上面更复杂的示例：

{% blocktrans count counter=list|length %}
There is only one {{ name }} object.
{% plural %}
There are {{ counter }} {{ name }} objects.
{% endblocktrans %}

Answer 2

http://docs.djangoproject.com/en/dev/topics/i18n/internationalization/#blocktrans-template-tag

{% blocktrans with text_count=cnt|make_text_from_count count cnt=cnt %}
    and another city
{% plural %}
    and other {{ text_count }} cities
{% endblocktrans %}