我有这样的对象结构
var x = {
nextSlot: 30,
breakTime: [
['11:00', '14:00'], ['16:00', '18:00']
],
startTime: '8:00',
endTime: '20:00'
}
我想生成从 startTime 到 endTime 的时间段。但我不想在时间段中考虑 breakTime。输出应该是
['08:00','08:30','09:00','09:30','10:00','10:30','14:00','14:30','15:00','15:30', '17:30', '18:00', '18:30','19:00','19:30']
我实现了自己的逻辑。但这适用于; y 对于长度为 1 的 breaktime 数组。
// Check whether the startTime is less than endTime
while (moment(x.startTime, ['HH:mm']).format('HH:mm') < moment(x.endTime, ['HH:mm']).format('HH:mm')) {
for (let i = 0; i < x.breakTime.length; i++) {
// if startTime is greater then breakTime[i][0], and if starttime is less then breaktime[i][1],
//just add nextSlot to starttime
if (moment(x.startTime, ['HH:mm']).format('HH:mm') >= moment(x.breakTime[i][0], ['HH:mm']).format('HH:mm') && moment(x.startTime, ['HH:mm']).format('HH:mm') < moment(x.breakTime[i][1], ['HH:mm']).format('HH:mm')) {
x.startTime = moment(x.startTime, ['HH:mm']).add(x.nextSlot, 'm').format('HH:mm');
} else {
//otherwise, push the time to slot array and then increment it by nextSlot
slots.push(moment(x.startTime, ['HH:mm']).format('hh:mm'));
x.startTime = moment(x.startTime, ['HH:mm']).add(x.nextSlot, 'm').format('HH:mm');
}
}
}
如果我再添加一个数组元素到breakTime
.