android - 如何在 OnPause 和 OnResume 状态下处理 ToggleButton 状态

Question

我面临切换按钮状态onResume()和onPause()状态的问题。

Activity - A（第一个用户打开按钮）然后返回到 Activity - B，然后它会返回到 Activity - A 然后我想要切换按钮打开而不是关闭，如何在 android 中处理这种状态。

Answer 1

默认情况下Activity处理具有id属性的组件状态。

如果不是这样，您可以使用onSaveInstanceStateandonRestoreInstanceState手动处理组件状态：

@Override
public void onSaveInstanceState(Bundle savedInstanceState) {
  super.onSaveInstanceState(savedInstanceState);

  savedInstanceState.putBoolean("Toggle1", toggle.isChecked());
  // etc.
}

并恢复状态：

@Override
public void onRestoreInstanceState(Bundle savedInstanceState) {
  super.onRestoreInstanceState(savedInstanceState);

  boolean toggle1State = savedInstanceState.getBoolean("Toggle1");
  toggle1.setCheched(toggle1State);
}

Answer 2

 toggle_relative.setOnToggleChanged(new ToggleButton.OnToggleChanged() {
        @Override
        public void onToggle(boolean on) {
            if (on == true){
                SharedPreferences.Editor editor = preferences.edit();
                editor.putBoolean("toggle_relative", true); // value to store
                editor.commit();
                Toast.makeText(getContext(),"Relatives will be notified in case of accidental situation",Toast.LENGTH_LONG).show();
            }else {
                SharedPreferences.Editor editor = preferences.edit();
                editor.putBoolean("toggle_relative", false); // value to store
                editor.commit();
            }
        }
    });







  @Override
public void onResume() {
    super.onResume();

    boolean boll_toggle_relative = preferences.getBoolean("toggle_relative", false);  //default is true
    if (boll_toggle_relative == true)
    {
        toggle_relative.setToggleOn();
    }
    else
    {
        toggle_relative.setToggleOff();
    }

}