5

我创建了一个Node项目passport。当我没有将令牌作为标题时,它会返回Unauthorized。如何将此消息更改为漂亮Sorry invalid credentials

每次无法提供令牌时,我都会得到未经授权的响应。我想把它改成漂亮的信息。

护照.js

const JwtStrategy = require('passport-jwt').Strategy;
const ExtractJwt = require('passport-jwt').ExtractJwt;
const mongoose = require('mongoose');

var User        = require('../models/user'); // get the mongoose model

const keys = require('../config/keys');

const opts = {};

opts.jwtFromRequest = ExtractJwt.fromAuthHeaderAsBearerToken();
opts.secretOrKey = keys.secretOrKey;

module.exports = passport => {
    passport.use(
        new JwtStrategy(opts, (jwt_payload, done) => {
            User.findById(jwt_payload.id)
                .then(user => {
                    if (user) {
                        return done(null, user);
                    }
                    return done(null, false);
                })
                .catch(err => console.log(err))
        })
    );
};

用户路由.js

const express = require('express');
const router = express.Router();
const jwt = require('jsonwebtoken');
const passport = require('passport');
const setting=require("../validation/settings");


const User = require('../models/user');


// *** GET *** /api/users/all *** Retrieve all users' basic details ***
router.get("/", passport.authenticate('jwt', {session: false}), function (req, res)
{
    var token = getToken(req.headers);
  console.log('the token: ' + token);

    User.find()
    .select('fname lname email avatar contact_no role')
    .where('is_deleted').equals('false')
    .exec()
    .then(docs => {
        return res.send(setting.status("User details retrieval successfully",false, "User details retrieval successfully", docs))
        //res.status(200).json(setting.status(validation.SHOW,true,"User details retrieval successfully.",docs))
    .catch(err => {
        return res.send(setting.status("Error in retrieving user details",false, "Error may token", err))
    });
    });
});


getToken = function (headers) {
  if (headers && headers.authorization) {
    var parted = headers.authorization.split(' ');
    if (parted.length === 2) {
      return parted[1];
    } else {
      return null;
    }
  } else {
    return null;
  }
};


module.exports = router;

如何将unauthorized消息更改为漂亮(“您无法获取详细信息”)

4

1 回答 1

4

根据您的官方文档,Passport可以使用自定义回调函数来处理授权失败的情况并覆盖默认消息。

如果您正在开发 REST API,然后您希望发送漂亮的 JSON 响应,如下所示:

{
    "error": {
        "name": "JsonWebTokenError",
        "message": "invalid signature"
    },
    "message": "You cannot get the details. You are not authorized to access this protected resource",
    "statusCode": 401,
    "data": [],
    "success": false
}

我正在使用Passport JWT身份验证来保护我的一些路由,并应用authMiddleware如下:

应用程序/中间件/authMiddleware.js

const express = require('express');
const router = express.Router();
const passport = require('passport');
const _ = require('lodash');

router.all('*', function (req, res, next) {
  passport.authenticate('jwt', { session: false }, function(err, user, info) {

    // If authentication failed, `user` will be set to false. If an exception occurred, `err` will be set.
    if (err || !user || _.isEmpty(user)) {
      // PASS THE ERROR OBJECT TO THE NEXT ROUTE i.e THE APP'S COMMON ERROR HANDLING MIDDLEWARE
      return next(info);
    } else {
      return next();
    }
  })(req, res, next);
});

module.exports = router;

应用程序/路由/approutes.js

const authMiddleware = require('../middlewares/authMiddleware');

module.exports = function (app) {
  // secure the route by applying authentication middleware
  app.use('/users', authMiddleware);
  .....
  ...
  ..

  // ERROR-HANDLING MIDDLEWARE FOR SENDING ERROR RESPONSES TO MAINTAIN A CONSISTENT FORMAT
  app.use((err, req, res, next) => {
    let responseStatusCode = 500;
    let responseObj = {
      success: false,
      data: [],
      error: err,
      message: 'There was some internal server error',
    };

    // IF THERE WAS SOME ERROR THROWN BY PREVIOUS REQUEST
    if (!_.isNil(err)) {
      // IF THE ERROR IS REALTED TO JWT AUTHENTICATE, SET STATUS CODE TO 401 AND SET A CUSTOM MESSAGE FOR UNAUTHORIZED
      if (err.name === 'JsonWebTokenError') {
        responseStatusCode = 401;
        responseObj.message = 'You cannot get the details. You are not authorized to access this protected resource';
      }
    }

    if (!res.headersSent) {
      res.status(responseStatusCode).json(responseObj);
    }
  });
};
于 2019-06-24T04:50:36.477 回答