4

我有多个包含重复代码的类，尤其是成员和最重要的静态方法，它将创建该类的新实例并返回此实例：以前在字典中注册的实例或通过调用构造函数的新实例。

接口是没有选择的，因为我有静态方法。我试图通过引入实现此静态方法的基类来解决该问题，但我找不到正确创建和返回特定子类的方法。

下面是当前情况的代码示例，A 类和 B 类显示重复代码。

public class A
{
    private static readonly IDictionary<string, A> Registry = new Dictionary<string, A>();
    public string Name { get; set; }

    public A(string name)
    {
        this.Name = name;
    }

    public static A GetA(string instanceName)
    {
        lock (Registry)
        {
            if (!Registry.TryGetValue(instanceName, out var newInstance))
            {
                newInstance = new A(instanceName);
            }
            return newInstance;
        }
    }
}

然后在 B 类中再次有一个成员 Name 和 GetX() 方法。

public class B
{
    private static readonly IDictionary<string, B> Registry = new Dictionary<string, B>();
    public string Name { get; set; }

    public B(string name)
    {
        this.Name = name;
    }

    public static B GetB(string instanceName)
    {
        lock (Registry)
        {
            if (!Registry.TryGetValue(instanceName, out var newInstance))
            {
                newInstance = new B(instanceName);
            }
            return newInstance;
        }
    }
}

是否有可能通过引入基类或任何其他方式来避免这种代码重复？

4

4 回答 4

2

这可能会更干净一点：

public class B: RegistryInstance<B>
{
    public string Name { get; set; }

    public B(string name)
    {
        this.Name = name;
    }
}

public class A : RegistryInstance<A>
{
    public string Name { get; set; }

    public A(string name)
    {
        this.Name = name;
    }
}

public abstract class RegistryInstance<T> where T:class
{
    protected static readonly IDictionary<string, T> Registry = new Dictionary<string, T>();

    public static T GetInstance(string instanceName)
    {
        lock (Registry)
        {
            if (!Registry.TryGetValue(instanceName, out var newInstance))
            {
                newInstance = (T)Activator.CreateInstance(typeof(T), new object[] { instanceName });
                Registry.Add(instanceName, newInstance);
            }
            return newInstance;
        }
    }
}
于 2019-01-03T10:38:15.037 回答
1

您在寻找通用基类吗？

public abstract class BaseRegistryGetter<T>
{
    private static readonly IDictionary<string, T> Registry = new Dictionary<string, T>();
    public string Name { get; set; }

    public BaseRegistryGetter(string name)
    {
        this.Name = name;
    }

    public static T GetValue (string instanceName, Func<string, T> creator) {
        lock (Registry)
        {
            if (!Registry.TryGetValue(instanceName, out var newInstance))
            {
                newInstance = creator(instanceName);
            }
            return newInstance;
        }
    }
}

然后像这样使用它：

public class A : BaseRegistryGetter<A>
{
    public A(string name) : base(name)
    {
    }

    public static A GetA(string instanceName)
    {
        return BaseRegistryGetter<A>.GetValue(instanceName, s => new A(s));
    }
}

可以在此处找到确保 A 存在字符串构造函数的笨拙方法的来源。

于 2019-01-03T10:31:40.457 回答
0

所有其他答案都试图用泛型解决这个问题，但你可能不想这样做。首先，这可能是一个不必要的限制，最终可能导致差异问题。其次，它只解决了一层继承，如果有更多，你又会遇到同样的问题：

 class Base<T> { ... }
 class A: Base<A> { ... }
 class B: A { //How does the generic base class help? }

没有使用泛型的通用解决方案只需要一点代码重复。一种可能是：

public class Base
{
    static readonly IDictionary<string, Base> Registry = 
        new Dictionary<string, Base>();

    protected static Base GetBase(string instanceName,
                                  Func<Base> creator)
    {
        lock (Registry)
        {
            if (!Registry.TryGetValue(instanceName, out var newInstance))
            {
                newInstance = creator();
            }   

            return newInstance;
        }
    }

    //...
}

现在你的派生类型可以实现一个强类型的委托方法：

public class A: Base
{
    public A(string instanceName)
        :base(instanceName)
    {
    }
    public static A GetA(string instanceName)
        => GetBase(instanceName, () => new A(instanceName)) as A;
}

public class B: Base
{
    public B(string instanceName)
        :base(instanceName)
    {
    }
    public static B GetB(string instanceName)
        => GetBase(instanceName, () => new B(instanceName)) as B;
}
于 2019-01-03T11:00:36.160 回答
0

我认为这应该有效。您可以对其进行调整以满足您的需求。Registry此外，您的代码中有一个错误：您在创建新实例时忘记添加。

class Program
{
    static void Main(string[] args)
    {
        A a1 = A.GetInstance("a");
        A a2 = A.GetInstance("aa");
        A a3 = A.GetInstance("a");

        B b1 = B.GetInstance("a");
        B b2 = B.GetInstance("aa");
        B b3 = B.GetInstance("a");

        Console.WriteLine(a1 == a2); //false
        Console.WriteLine(a1 == a3); //true

        Console.WriteLine(b1 == b2); //false
        Console.WriteLine(b1 == b3); //true

        Console.ReadKey();
    }
}

public class A : Generic<A>
{
    public A(string name)
        : base(name)
    {
    }
}

public class B : Generic<B>
{
    public B(string name)
        : base(name)
    {
    }
}

public abstract class Generic<T> where T : Generic<T>
{
    private static readonly IDictionary<string, T> Registry = new Dictionary<string, T>();
    public string Name { get; set; }

    public Generic(string name)
    {
        this.Name = name;
    }

    public static T GetInstance(string instanceName)
    {
        lock (Registry)
        {
            if (!Registry.TryGetValue(instanceName, out var newInstance))
            {
                newInstance = (T)Activator.CreateInstance(typeof(T), instanceName);
                Registry.Add(instanceName, newInstance);
            }
            return newInstance;
        }
    }
}
于 2019-01-03T10:37:38.777 回答