qt - 类'QSharedPointer的构造函数' 被声明为 'explicit' - 如何解决此错误

Question

尝试使用时出现以下错误：

typedef QSharedPointer<Test> CTest


CTest* Module::function(params)
{
    CTestNew* ptr = new CTestNew(params);

    dosomething();

    return ptr;
}

然后在代码中用 CTest 替换 Test*。我错过了什么？

error C2664: 'QSharedPointer<T>::QSharedPointer(const QSharedPointer<T> &)' : cannot convert parameter 1 from 'CTestNew*' to 'const QSharedPointer<T> &'
            with
            [
               T=Test
            ]
            Reason: cannot convert from 'CTestNew *' to 'const QSharedPointer<T>'
            with
            [
                T=Test
           ]
            Constructor for class 'QSharedPointer<T>' is declared 'explicit'
            with
            [
                T=Test
            ]

Answer 1

编译器错误的说法CTestNew不一样Test

编辑：回应评论说CTestNew是摘要的子类Test

CTest* Module::function(params)
{
    CTestNew* ptr = new CTestNew(params);
    dosomething();
    return ptr;
}

应该：

CTest Module::function(params) // Don't return a pointer to a shared pointer
{
    Test * ptr = new Test(params); // You're using Test not CTestNew in the CTest typedef
    dosomething();
    return CTest(static_cast<Test *>(ptr));
}