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我有一个奇怪的问题:我的本地机器和服务器上有 MySQL v5.7.24。以下代码在本地执行良好:

DROP FUNCTION IF EXISTS SharingRatio;

CREATE FUNCTION SharingRatio(users int, sharer int, cabins int, outdoors int) RETURNS DECIMAL(6,2)
    DETERMINISTIC
    READS SQL DATA
BEGIN
    DECLARE ratio DECIMAL(6,2);

    IF cabins IS NULL THEN
     SET cabins = 0;
    END IF;

    IF sharer IS NULL THEN
     SET sharer = 1;
    END IF;

    IF users IS NULL THEN
     SET users = 1;
    END IF;

    SELECT  IF(sharer = 1, telco1, IF(sharer = 2, telco2, IF(sharer = 3, telco3, IF(sharer =4, telco4, IF(sharer = 5, telco5, null)))))
    FROM rates r WHERE (r.type='Utility' and r.cabin = cabins and if(outdoors IS NULL, true, r.outdoor = outdoors) and r.users = users) LIMIT 1 INTO ratio;

    IF ratio IS NULL THEN
       SET ratio = ROUND(100 / users, 2) ;
    END IF;

 RETURN (ratio);
END;


DROP FUNCTION IF EXISTS SharingValue;

CREATE FUNCTION SharingValue(value decimal(10,2), users int, sharer int, cabins int, outdoors int) RETURNS DECIMAL(10,2)
    DETERMINISTIC
    READS SQL DATA
BEGIN
    DECLARE ratio DECIMAL(6,2);

    IF value IS NULL THEN
       RETURN NULL;
    END IF;

    IF cabins IS NULL THEN
     SET cabins = 0;
    END IF;

    IF sharer IS NULL THEN
     SET sharer = 1;
    END IF;

    IF users IS NULL THEN
     SET users = 1;
    END IF;

    SET ratio = SharingRatio(users, sharer, cabins, outdoors);

 RETURN CAST(value * (ratio / 100) AS DECIMAL(10,2));
END;

但是,当我通过 MySQLAdmin 部署具有 root 访问权限时,我收到了臭名昭著的#1064 错误,即在第 5 行靠近 '' 时出现错误

我查看了许多其他帖子,没有悬空的逗号,没有 ELSE IF 引起问题。坦率地说,我被困住了!

4

1 回答 1

1

解决了!

有分隔符标签是问题。正确的代码是:

DROP FUNCTION IF EXISTS SharingRatio;
DELIMITER $$
CREATE FUNCTION SharingRatio(users int, sharer int, cabins int, outdoors int)

RETURNS DECIMAL(6,2)
DETERMINISTIC READS SQL DATA

BEGIN
    DECLARE ratio DECIMAL(6,2);

    IF cabins IS NULL THEN
     SET cabins = 0;
    END IF;

    IF sharer IS NULL THEN
     SET sharer = 1;
    END IF;

    IF users IS NULL THEN
     SET users = 1;
    END IF;

    SELECT  IF(sharer = 1, telco1, IF(sharer = 2, telco2, IF(sharer = 3, telco3, IF(sharer =4, telco4, IF(sharer = 5, telco5, null)))))
    FROM rates r WHERE (r.type='Utility' and r.cabin = cabins and if(outdoors IS NULL, true, r.outdoor = outdoors) and r.users = users) LIMIT 1 INTO ratio;

    IF ratio IS NULL THEN
       SET ratio = ROUND(100 / users, 2);
    END IF;

 RETURN (ratio);
END$$

DELIMITER ;

DROP FUNCTION IF EXISTS SharingValue;

DELIMITER $$

CREATE FUNCTION SharingValue(value decimal(10,2), users int, sharer int, cabins int, outdoors int)

RETURNS DECIMAL(10,2)
DETERMINISTIC
READS SQL DATA

BEGIN
    DECLARE ratio DECIMAL(6,2);

    IF value IS NULL THEN
       RETURN NULL;
    END IF;

    IF cabins IS NULL THEN
     SET cabins = 0;
    END IF;

    IF sharer IS NULL THEN
     SET sharer = 1;
    END IF;

    IF users IS NULL THEN
     SET users = 1;
    END IF;

    SET ratio = SharingRatio(users, sharer, cabins, outdoors);

 RETURN CAST(value * (ratio / 100) AS DECIMAL(10,2));
END$$
DELIMITER ;
于 2018-12-21T03:50:33.610 回答