0

首先，我从以下查询生成了一个表：

select su.supplier_zip, sp.shop_zip, COUNT(p.ptypes) 
from supplier su 
inner join parts p on su.sid=p.sid 
inner join sales s on p.parts_pid=s.pid 
inner join shop sp on s.shop_id=sp.shop_id 
group by sp.shop_zip, su.supplier_zip 
order by su.supplier_zip;

+--------------+----------+-----------------+
| supplier_zip | shop_zip | COUNT(p.ptypes) |
+--------------+----------+-----------------+
|         7733 |    85254 |               6 |
|         7733 |    33603 |               2 |
|         7733 |    92821 |               7 |
|         7733 |    95070 |               2 |
|         7733 |    94010 |               5 |
|         7733 |    68154 |               6 |
|         7733 |    45277 |               4 |
|         7733 |    94568 |               3 |
|         7733 |    55401 |               3 |
|         7733 |    85308 |               5 |
|         7733 |    85226 |               6 |
|         7733 |    11021 |               3 |
|         7733 |    35243 |               5 |
|         7733 |     7764 |               3 |
|         7733 |    26505 |               1 |
|        26505 |    85226 |               6 |
|        26505 |    55401 |               4 |
|        26505 |    92821 |               5 |
|        26505 |    45277 |               1 |
|        26505 |    26505 |               6 |
|        26505 |    94568 |               4 |
|        26505 |    85254 |               6 |
...

我正在尝试列出 COUNTS 的最小值。所以我在一个选择中做了一个选择，我最终得到：

+-------------+---------+-----------+
| supplierzip | shopzip | MIN(type) |
+-------------+---------+-----------+
|        7733 |   55401 |         1 |
|       26505 |   85308 |         1 |
|       33603 |   94568 |         3 |
|       45277 |   33603 |         1 |
|       55401 |   55401 |         1 |
|       60601 |   85254 |         3 |
|       68154 |   94568 |         2 |
|       85226 |   85226 |         6 |
|       92821 |   85226 |         5 |
|       94568 |   45277 |         2 |
+-------------+---------+-----------+

使用查询：

select supplierzip, shopzip, MIN(type) 
from (
select su.supplier_zip as supplierzip, sp.shop_zip as shopzip, COUNT(p.ptypes) as type 
from supplier su 
inner join parts p on su.sid=p.sid 
inner join sales s on p.parts_pid=s.pid 
inner join shop sp on s.shop_id=sp.shop_id 
group by sp.shop_zip, su.supplier_zip 
order by su.supplier_zip)a 
group by supplierzip;

结果是不对的。因为当您查看供应商zip-7733 时，shopzip 应该是 26505，MIN(num) 为 1。但这不是我得到的答案。

4

1 回答 1

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改为使用窗口最小值：

SELECT
    supplierzip
  , shopzip
  , MIN( type ) over(partition by supplierzip)
FROM (
    SELECT
        su.supplier_zip   AS supplierzip
      , sp.shop_zip       AS shopzip
      , COUNT( p.ptypes ) AS type
    FROM supplier su
    INNER JOIN parts p ON su.sid = p.sid
    INNER JOIN sales s ON p.parts_pid = s.pid
    INNER JOIN shop sp ON s.shop_id = sp.shop_id
    GROUP BY
        su.supplier_zip 
      , sp.shop_zip
    ) a
ORDER BY
    supplierzip
  , shopzip

请注意，没有理由在子查询中使用 order by。

请注意，ONLY_FULL_GROUP_BY 现在是 MariaDB 和 MySQL 的默认行为，坦率地说，应该一直是（在我看来）。请参阅分组依据。

以您在问题中显示的结果为例：

+-------------+---------+-----------+
| supplierzip | shopzip | MIN(type) |
+-------------+---------+-----------+
|        7733 |   55401 |         1 |

源自：

| supplier_zip | shop_zip | COUNT(p.ptypes) |
+--------------+----------+-----------------+
|         7733 |    85254 |               6 |
|         7733 |    33603 |               2 |
|         7733 |    92821 |               7 |
|         7733 |    95070 |               2 |
|         7733 |    94010 |               5 |
|         7733 |    68154 |               6 |
|         7733 |    45277 |               4 |
|         7733 |    94568 |               3 |
|         7733 |    55401 |               3 |  <<== why is 55401 chosen???
|         7733 |    85308 |               5 |
|         7733 |    85226 |               6 |
|         7733 |    11021 |               3 |
|         7733 |    35243 |               5 |
|         7733 |     7764 |               3 |
|         7733 |    26505 |               1 |

但是对于 shopzip 55401 的选择没有明显的逻辑。这（看起来）是 ONLY_FULL_GROUP_BY 未启用时使用的“近似值”。

于 2018-12-15T03:04:22.447 回答