3

I'm trying to read html code from a URL Connection. In one case the html file I'm trying to read includes 5 line breaks before the actual doc type declaration. In this case the input reader throws an exception for EOF.

URL pageUrl = 
    new URL(
        "http://www.nytimes.com/2011/03/15/sports/basketball/15nbaround.html"
    );

URLConnection getConn = pageUrl.openConnection();
getConn.connect();
DataInputStream dis = new DataInputStream(getConn.getInputStream());
//some read method here

Has anyone ran into a problem like this?

URL pageUrl = new URL("http://www.nytimes.com/2011/03/15/sports/basketball/15nbaround.html");
URLConnection getConn = pageUrl.openConnection();
getConn.connect();
DataInputStream dis = new DataInputStream(getConn.getInputStream());
String urlData = "";
while ((urlData = dis.readUTF()) != null)
    System.out.println(urlData);

//exception thrown

java.io.EOFException at java.io.DataInputStream.readUnsignedShort(DataInputStream.java:323) at java.io.DataInputStream.readUTF(DataInputStream.java:572) at java.io.DataInputStream.readUTF(DataInputStream.java:547)

in the case of bufferedreader, it just responds null and doesn't continue

pageUrl = new URL("http://www.nytimes.com/2011/03/15/sports/basketball/15nbaround.html");
URLConnection getConn = pageUrl.openConnection();
getConn.connect();
BufferedReader br = new BufferedReader(new InputStreamReader(getConn.getInputStream()));
String urlData = "";
while(true)
     urlData = br.readLine();
     System.out.println(urlData);

outputs null

4

3 回答 3

1

DataInputStream用于读取未使用DataOutputStream. 检查您调用的记录在案的行为DataInputStream#readUtf()它首先读取两个字节以形成一个 16 位整数,表示后面包含 UTF 编码字符串的字节数。您从 HTTP 服务器读取的数据不是以这种格式编码的。

相反,HTTP 服务器根据RFC 2616第 6.1 和 2.2 节发送以 ASCII 编码的标头。您需要将标头作为文本读取,然后确定消息正文(“实体”)的编码方式。

于 2011-03-20T22:52:46.687 回答
1

这工作正常:

package url;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.Reader;
import java.net.URL;

/**
 * UrlReader
 * @author Michael
 * @since 3/20/11
 */
public class UrlReader
{

    public static void main(String[] args)
    {
        UrlReader urlReader = new UrlReader();

        for (String url : args)
        {
            try
            {
                String contents = urlReader.readContents(url);
                System.out.printf("url: %s contents: %s\n", url, contents);
            }
            catch (Exception e)
            {
                e.printStackTrace();
            }
        }
    }


    public String readContents(String address) throws IOException
    {
        StringBuilder contents = new StringBuilder(2048);
        BufferedReader br = null;

        try
        {
            URL url = new URL(address);
            br = new BufferedReader(new InputStreamReader(url.openStream()));
            String line = "";
            while (line != null)
            {
                line = br.readLine();
                contents.append(line);
            }
        }
        finally
        {
            close(br);
        }

        return contents.toString();
    }

    private static void close(Reader br)
    {
        try
        {
            if (br != null)
            {
                br.close();
            }
        }
        catch (Exception e)
        {
            e.printStackTrace();
        }
    }
}
于 2011-03-20T23:01:25.787 回答
0

这个:

public class Main {
    public static void main(String[] args) 
        throws MalformedURLException, IOException 
    {
        URL pageUrl = new URL("http://www.google.com");
        URLConnection getConn = pageUrl.openConnection();
        getConn.connect();
        BufferedReader dis = new BufferedReader( 
                                 new InputStreamReader(
                                     getConn.getInputStream()));
        String myString;
        while ((myString = dis.readLine()) != null)
        {
            System.out.println(myString);
        }
    }
}

完美运行。但是,您提供的 URL 不返回任何内容。

于 2011-03-20T22:50:42.747 回答