0

只是想知道您是否可以在 android 中使用 shift 运算符我在尝试时遇到语法错误。运算符是 >> << >>> 。如果它不支持它是他们的 android sdk 等价物吗？

编辑：这是我正在使用的代码。我正在尝试进行每像素碰撞检测并尝试了这一点。

公共无效getBitmapData（位图位图1，位图位图2）{
     int[] bitmap1Pixels;
     int[] bitmap2Pixels;


    int bitmap1Height = bitmap1.getHeight();
    int bitmap1Width = bitmap1.getWidth();
    int bitmap2Height = bitmap1.getHeight();
    int bitmap2Width = bitmap1.getWidth();
    bitmap1Pixels = new int[bitmap1Height * bitmap1Width];
    bitmap2Pixels = new int[bitmap2Height * bitmap2Width];

    bitmap1.getPixels(bitmap1Pixels, 0, bitmap1Width, 1, 1, bitmap1Width - 1, bitmap1Height - 1); 
    bitmap2.getPixels(bitmap2Pixels, 0, bitmap2Width, 1, 1, bitmap2Width - 1, bitmap2Height - 1); 


 // Find the first line where the two sprites might overlap
    int linePlayer, lineEnemy;
    if (ninja.getY() <= enemy.getY()) {
        linePlayer = enemy.getY() - ninja.getY();
        lineEnemy = 0;
    } else {
        linePlayer = 0;
        lineEnemy = ninja.getY() - enemy.getY();
    }
    int line = Math.max(linePlayer, lineEnemy);

    // Get the shift between the two
    int x = ninja.getX() - enemy.getX();
    int maxLines = Math.max(bitmap1Height, bitmap2Height);
    for (; line <= maxLines; line ++) {
        // if width > 32, then you need a second loop here
        long playerMask = bitmap1Pixels[linePlayer];
        long enemyMask = bitmap2Pixels[lineEnemy];
        // Reproduce the shift between the two sprites
        if (x < 0) playerMask << (-x);
        else enemyMask << x;
        // If the two masks have common bits, binary AND will return != 0
        if ((playerMask & enemyMask) != 0) {
            // Contact!
            Log.d("pixel collsion","we have pixel on pixel");
        }

    }



}
4

2 回答 2

2

如果你要附加到一个字符串，你会得到一个错误，除非你把算术运算放在括号中：


jcomeau@intrepid:/tmp$ cat test.java
public class test {
 public static void main(String args[]) {
  int test = 42;
  System.out.println("" + (test >> 1) + ", " + (test << 1) + ", " + (test >>> 1));
 }
}
jcomeau@intrepid:/tmp$ java test
21, 84, 21
于 2011-03-19T23:58:27.700 回答
1

Android 使用的 Java 确实支持按位运算。这是一个方便的指南。

于 2011-03-19T23:55:40.600 回答