9

我经常需要比较某种类型的实例是否相等,但我不需要比较所有内容,只需要比较某些字段。我通常这样做:

Comparator<SomeType> c = Comparator.comparing(SomeType::getNumber)
  .thenComparing(SomeType::getType)
  .thenComparing(SomeType::getSite)
  .thenComparing(SomeType::getAddition)
  .thenComparing(SomeType::getImportantFlag);

if (c.compare(old, new) == 0) {
...
}

正如我经常这样做的那样,我想知道是否有一种通用的方法可以做到这一点。
我必须比较的所有对象都扩展了某个基类。有没有办法编写一个可以为我做所有这些比较的静态方法?我正在考虑一个静态方法,它必须为要比较的对象提供参数,并为所有方法引用提供一个可变参数:

public static <T extends BaseType> boolean areFieldsEqual(T left, T right, whatShouldIPutHere... fields) {
}

但我不知道如何传递方法引用以及如何在方法内的比较器中使用它们。这可以以某种方式完成还是我应该尝试不同的方法?

4

3 回答 3

3

我设法想出了一些似乎可行的方法:

public static <T extends BaseType> boolean areFieldsEqual(T left, T right, Function<T,? extends Comparable>... fields)
{
    if (fields.length < 1) {
        return true;
    }
    Comparator<T> c = Comparator.comparing(fields[0]);
    for (int i = 1; i < fields.length; i++) {
        c = c.thenComparing (fields[i]);
    }
    return c.compare(left, right) == 0;
}

测试类:

class BaseType {
    String x;
    int y;
    public BaseType (String x, int y) {
        this.x=x;
        this.y=y;
    }
    String getX () {return x;}
    int getY () { return y;}
}

class SubType extends BaseType {
    String z;

    public SubType (String x, int y,String z) {
        super(x,y);
        this.z=z;
    }
    String getZ () {return z;}
}

用法:

BaseType one = new BaseType("some",1);
BaseType two = new BaseType("some",2);
SubType three = new SubType("some",1,"else");
SubType four = new SubType("some",2,"else");
System.out.println (areFieldsEqual(one,two,BaseType::getX,BaseType::getY));
System.out.println (areFieldsEqual(three,four,SubType::getZ,BaseType::getX));

输出:

false
true
于 2018-12-04T11:39:54.593 回答
2

使用varargs泛型将导致编译器警告,如Potential heap pollution via varargs parameter. 通常为了避免这种情况,我们可以提供如下几个函数:

  1. 单场:

    public static <T extends BaseType> boolean areFieldsEqual(
      T first, T second, Function<? super T, ? extends Comparable> keyExtractor) {
        Comparator<T> comp = Comparator.comparing(keyExtractor);
        return comp.compare(first, second) == 0;
    }
    
  2. 有两个字段:

    public static <T extends BaseType> boolean areFieldsEqual(
          T first, T second, Function<T, ? extends Comparable> firstField,
          Function<T, ? extends Comparable> secondField) {
        Comparator<T> comp = Comparator.comparing(firstField).thenComparing(secondField);
        return comp.compare(first, second) == 0;
    }
    
  3. 使用varargs. 由于我们没有存储任何内容,因此fields我们可以@SafeVarargs通过此方法使用:

    @SafeVarargs
    public static <T extends BaseType> boolean areFieldsEqual(
      T first, T second, Function<T, ? extends Comparable>... fields) {
        if (fields.length < 1) {
          return true;
        }
        Comparator<T> comp = Comparator.comparing(fields[0]);
        for (int i = 1; i < fields.length; i++) {
          comp = comp.thenComparing(fields[i]);
        }
        return comp.compare(first, second) == 0;
    }
    
于 2018-12-04T11:55:30.487 回答
1

这是您可以使用的基本思想:

List<Function<SomeType, Comparable>> fieldsToTest = new ArrayList<>();
fieldsToTest.add(SomeType::getType);
fieldsToTest.add(SomeType::getSite);
System.out.println(areFieldsEqual(new SomeType(...), new SomeType(...), fieldsToTest));

areFieldsEqual方法实现:

static <T extends BaseType> boolean areFieldsEqual(T left, T right, 
                                                   List<Function<T, Comparable>> fields) {
    Comparator<T> c = fields.stream().reduce(
        (l, r) -> 0, Comparator::thenComparing, Comparator::thenComparing);
    return c.compare(left, right) == 0;
}

或者,如果您想坚持使用该varargs参数:

static <T extends BaseType> boolean areFieldsEqual(T left, T right,
                                                   Function<T, Comparable>... fields) {
    Comparator<T> c = Arrays.stream(fields).reduce(
        (l, r) -> 0, Comparator::thenComparing, Comparator::thenComparing);
    return c.compare(left, right) == 0;
}
于 2018-12-04T12:04:42.183 回答