3

我有一个从多个 API 获取数据的应用程序。为了尽量减少类的数量,我需要映射到每个属性。我已经实现了一个简单的 json.net ContractResolver。但是,当我尝试将属性映射到子属性时,我遇到了一些麻烦。

JSON格式1:

{
    "event_id": 123,
    "event_name": "event1",
    "start_date": "2018-11-30",
    "end_date": "2018-12-04",
    "participants": {
        "guests": [
            {
                "guest_id": 143,
                "first_name": "John",
                "last_name": "Smith",               
            },
            {
                "guest_id": 189,
                "first_name": "Bob",
                "last_name": "Duke",    
            }
        ]
    }
}

JSON格式2:

{
    "name": "event2",
    "from": "2017-05-05",
    "to": "2017-05-09",
    "city":"Some other city",
    "country":"US",
    "guests": [
        {
            "email":"jane@smith.com",
            "firstName":"Jane",
            "lastName":"Smith",
            "telephone":"1-369-81891"
        }
    ],
}

这是我的模型类:

public class Event
{
    public int EventId { get; set; }
    public string EventName { get; set; }
    public DateTime StartDate { get; set; }
    public DateTime EndDate { get; set; }
    public List<Guest> Guests { get; set; }
}

public class Guest
{
    public string GuestId { get; set; }
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public string Email { get; set; }       
}

还有我的解析器:

public class EventResolver : DefaultContractResolver
{
    private Dictionary<string,string> PropertyMappings { get; set; }

    public EventResolver()
    {
        this.PropertyMappings = new Dictionary<string, string>
        {
            {"EventId", "event_id"},
            {"StartDate", "start_date" },
            {"EndDate", "end_date" },
            {"EventName", "event_name" },
            {"Guests", "participants.guests"}
        };
    }

    protected override JsonContract CreateContract(Type objectType)
    {
        return base.CreateContract(objectType);
    }

    protected override string ResolvePropertyName(string propertyName)
    {
        var resolved = this.PropertyMappings.TryGetValue(propertyName, out var resolvedName);
        return (resolved) ? resolvedName : base.ResolvePropertyName(propertyName);
    }
}

我知道路径不能代替属性名称。怎么可能这样?

4

2 回答 2

1

我认为解析器的想法不会奏效,因为您不仅要重新映射属性名称 - 您还试图反序列化为一个并不总是与 JSON 的形状匹配的类结构。这项工作更适合一组JsonConverters。

这是基本方法:

  1. 为 JSON 变化的每个模型类创建一个JsonConverter
  2. 在方法内部从阅读器ReadJson加载一个。JObject
  3. 通过查找该格式始终存在的知名属性名称来检测您使用的格式。例如,如果您可以依赖event_id始终以第一种格式存在,这是检测它的好方法,因为您知道第二种格式不具有该属性。如果需要,您可以根据是否存在多个属性进行此检查;关键是要使用一些仅以一种格式出现而没有其他格式的组合。(或者,如果您提前知道预期的格式,您可以简单地参数化转换器,即在构造函数中传递格式标志。)
  4. 知道格式后,从JObject.

对于Event您的问题中显示的模型,转换器可能如下所示:

public class EventConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(Event);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        Event evt = new Event();
        JObject obj = JObject.Load(reader);
        if (obj["event_id"] != null)
        {
            // JSON format #1
            evt.EventId = (int)obj["event_id"];
            evt.EventName = (string)obj["event_name"];
            evt.StartDate = (DateTime)obj["start_date"];
            evt.EndDate = (DateTime)obj["end_date"];
            evt.Guests = obj.SelectToken("participants.guests").ToObject<List<Guest>>(serializer);
        }
        else if (obj["name"] != null)
        {
            // JSON format #2
            evt.EventName = (string)obj["name"];
            evt.StartDate = (DateTime)obj["from"];
            evt.EndDate = (DateTime)obj["to"];
            evt.Guests = obj["guests"].ToObject<List<Guest>>(serializer);
        }
        else
        {
            throw new JsonException("Unknown format for Event");
        }
        return evt;
    }

    public override bool CanWrite
    {
        get { return false; }
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

同样对于Guest模型,我们可能有这个JsonConverter

public class GuestConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(Guest);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        Guest guest = new Guest();
        JObject obj = JObject.Load(reader);
        if (obj["guest_id"] != null)
        {
            // JSON format #1
            guest.GuestId = (string)obj["guest_id"];
            guest.FirstName = (string)obj["first_name"];
            guest.LastName = (string)obj["last_name"];
        }
        else if (obj["email"] != null)
        {
            // JSON format #2
            guest.FirstName = (string)obj["firstName"];
            guest.LastName = (string)obj["lastName"];
            guest.Email = (string)obj["email"];
        }
        else
        {
            throw new JsonException("Unknown format for Guest");
        }
        return guest;
    }

    public override bool CanWrite
    {
        get { return false; }
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

要使用转换器,请将它们添加到对象的Converters集合中JsonSerializerSettings并将设置传递给DeserializeObject()如下所示:

var settings = new JsonSerializerSettings
{
    Converters = new List<JsonConverter> { new EventConverter(), new GuestConverter() }
};

var evt = JsonConvert.DeserializeObject<Event>(json, settings);

演示小提琴:https ://dotnetfiddle.net/KI82KB

于 2018-12-04T21:08:37.450 回答
1

我认为你对它进行了过度设计,当你需要支持越来越多的格式和制作人时,它会变得一团糟。想象一下,如果你有 15 个不同格式的事件生产者,你的解析器会是什么样子?

您需要为您的域创建一组适合您的域和需求的类。

public class Event
{
    public int EventId { get; set; }
    public string EventName { get; set; }
    public DateTime StartDate { get; set; }
    public DateTime EndDate { get; set; }
    public List<Guest> Guests { get; set; }
}

public class Guest
{
    public string GuestId { get; set; }
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public string Email { get; set; }       
}

public interface IEventProvider
{
    Event[] GetEvents();
}

然后为每个外部生产者创建一组类并将其映射到您的域类,例如使用 AutoMapper 配置文件或手动映射。

namespace YourCompany.EventProvider.Api1
{
    // just an example with json2sharp, use data annotations if you want
    public class Guest
    {
        public int guest_id { get; set; }
        public string first_name { get; set; }
        public string last_name { get; set; }
    }

    public class Participants
    {
        public List<Guest> guests { get; set; }
    }

    public class RootObject
    {
        public int event_id { get; set; }
        public string event_name { get; set; }
        public string start_date { get; set; }
        public string end_date { get; set; }
        public Participants participants { get; set; }
    }

    public class Api1EventProvider : IEventProvider
    {
        public Event[] GetEvents()
        {
           RootObject[] api1Response = GetFromApi();
           return _mapper.Map<RootObject[], Event[]>(api1Response);
        }
    }       
}

是的,我会有更多的课。但是这段代码会更好、更易读、更易维护;您将花费更少的时间来创建它,而不是创建解析器;并且未来的开发者不会在每次生产者更改他的 API 时哭泣。
代码质量不是关于创建更少的类。

于 2018-12-04T11:59:02.763 回答