reactjs - 对讲机必须双击才能出现菜单。

Question

我必须双击我的支持按钮才能让对讲机出现在初始点击时

    private handleSupportClick() {
        const ic = (window as any).Intercom;
        function l() {
            const d = document;
            const s = d.createElement('script');
            s.type = 'text/javascript';
            s.async = true;
            s.src = 'https://widget.intercom.io/widget/';
            const x = d.getElementsByTagName('script')[0];
            (x as any).parentNode.insertBefore(s, x);
        }
        (window as any).intercomSettings = {
            app_id: process.env.REACT_APP_INTERCOM_APP_ID as string,
            hide_default_launcher: true
        };
        (() => {
            l();
            if (typeof ic === "function") {
                ic('reattach_activator');
                ic('show', (window as any).intercomSettings);
            } else {
                const i = (...args: any) => {
                    (i as any).c(...args)
                };
                (i as any).q = [];
                (i as any).c = (args: any) => {
                    (i as any).q.push(args)
                };
                (window as any).Intercom = i;
                this.handleSupportClick();
            }
        })()
    }

.

不过，在第一次点击之后，只需单击我的支持按钮即可召唤同一个信使。我已经逐行跟踪调试器中的流程，但我仍然找不到为什么这需要双击。当然，我已经在初始单击后再次调用了函数本身，但这仍然不起作用，并且我收到一条错误消息“在非对象上调用 CreateListFromArrayLike”

非常感谢任何和所有帮助。