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我的 .NET Core 应用程序中有以下 LINQ 代码。我正在使用带有 Pomelo 的 EF Core 作为 MySQL 的驱动程序。

var journeyId = 5917;
var journey = Journeys.FirstOrDefault(j => j.JourneyId == journeyId);

var journeyEvents = from ad in AccelerometerData
                    join ae in AccelerometerEvents on ad.AccelerometerDataId equals ae
                        .AccelerometerData.AccelerometerDataId
                    where ad.Device.DeviceId == journey.Device.DeviceId && ae.TimeStamp >= journey.StartDateTime &&
                          ae.TimeStamp <= journey.EndDateTime
                    group ae by new
                    {
                        ae.EventType,
                        ae.Level
                    } into g
                    select new
                    {
                        EventType = new JourneyEventType { JourneyEventTypeId = g.Key.EventType },
                        Level = g.Key.Level,
                        Count = g.ToList().Count()
                    };

journey.JourneyEvents = journeyEvents.ToList();

当代码尝试运行最后一行时,我得到以下异常。

无法解析表达式“g.ToList()”:当前不支持该方法“System.Linq.Enumerable.ToList”的重载。

我错过了什么?

4

2 回答 2

2

使用g.Count()代替 g.ToList().Count()。

var journeyEvents = from ad in AccelerometerData
                    join ae in AccelerometerEvents on ad.AccelerometerDataId equals ae
                        .AccelerometerData.AccelerometerDataId
                    where ad.Device.DeviceId == journey.Device.DeviceId && ae.TimeStamp >= journey.StartDateTime &&
                          ae.TimeStamp <= journey.EndDateTime
                    group ae by new
                    {
                        ae.EventType,
                        ae.Level
                    } into g
                    select new
                    {
                        EventType = new JourneyEventType { JourneyEventTypeId = g.Key.EventType },
                        Level = g.Key.Level,
                        Count = g.Count()
                    };

journey.JourneyEvents = journeyEvents.ToList();
于 2018-11-22T16:32:18.677 回答
0

我认为你应该在这里使用 SelectToMany:

g.SelectToMany(gr => gr).ToList().Count()
于 2018-11-22T17:40:59.073 回答