每当 googlemaps 视口中心发生变化时，我都会尝试使用邮政编码向我的数据库提交查询。我知道这可以通过反向地理编码来完成，例如：
google.maps.event.addListener(map, 'center_changed', function(){
newCenter();
});
...
function newCenter(){
var newc = map.getCenter();
geocoder.geocode({'latLng': newc}, function(results, status){
if (status == google.maps.GeocoderStatus.OK) {
var newzip = results[0].address_components['postal_code'];
}
});
};
当然，这段代码实际上不起作用。所以我想知道我需要如何更改它才能从结果数组中提取邮政编码。谢谢
到目前为止，我已经意识到，在大多数情况下，邮政编码始终是每个返回地址中的最后一个值，因此，如果您想检索第一个邮政编码（这是我的情况），您可以使用以下方法：
var address = results[0].address_components;
var zipcode = address[address.length - 1].long_name;
您可以使用 underscore.js 库轻松完成此操作：http ://documentcloud.github.com/underscore/#find
_.find(results[0].address_components, function (ac) { return ac.types[0] == 'postal_code' }).short_name
使用 jQuery？
var searchAddressComponents = results[0].address_components,
searchPostalCode="";
$.each(searchAddressComponents, function(){
if(this.types[0]=="postal_code"){
searchPostalCode=this.short_name;
}
});
short_name 或 long_name 将
在“searchPostalCode”上方工作，如果您从 Google Maps API 获得一个，则该变量将包含邮政（邮编？）代码。
有时您不会得到“postal_code”作为查询的回报。
好的，所以我明白了。该解决方案比我想要的要丑一些，而且我可能不需要最后一个 for 循环，但这是需要从 address_components[] 中提取废话的任何人的代码。这是在地理编码器回调函数中
// make sure to initialize i
for(i=0; i < results.length; i++){
for(var j=0;j < results[i].address_components.length; j++){
for(var k=0; k < results[i].address_components[j].types.length; k++){
if(results[i].address_components[j].types[k] == "postal_code"){
zipcode = results[i].address_components[j].short_name;
}
}
}
}
$.each(results[0].address_components,function(index,value){
if(value.types[0] === "postal_code"){
$('#postal_code').val(value.long_name);
}
});
这只需要两个 for 循环。一旦我们发现第一个“类型”是“postal_code”，“结果”数组就会更新。
然后它用新找到的数组集更新原始数组并再次循环。
var i, j,
result, types;
// Loop through the Geocoder result set. Note that the results
// array will change as this loop can self iterate.
for (i = 0; i < results.length; i++) {
result = results[i];
types = result.types;
for (j = 0; j < types.length; j++) {
if (types[j] === 'postal_code') {
// If we haven't found the "long_name" property,
// then we need to take this object and iterate through
// it again by setting it to our master loops array and
// setting the index to -1
if (result.long_name === undefined) {
results = result.address_components;
i = -1;
}
// We've found it!
else {
postcode = result.long_name;
}
break;
}
}
}
您也可以使用此代码，此功能将有助于在按钮单击或 onblur 或 keyup 或 keydown 时获取 zip。
只需将地址传递给此函数。
使用删除了有效密钥和传感器选项的 google api，因为它现在不需要。
function callZipAPI(addSearchZip)
{
var geocoder = new google.maps.Geocoder();
var zipCode = null;
geocoder.geocode({ 'address': addSearchZip }, function (results, status) {
if (status == google.maps.GeocoderStatus.OK) {
//var latitude = results[0].geometry.location.lat();
//var longitude = results[0].geometry.location.lng();
var addressComponent = results[0].address_components;
for (var x = 0 ; x < addressComponent.length; x++) {
var chk = addressComponent[x];
if (chk.types[0] == 'postal_code') {
zipCode = chk.long_name;
}
}
if (zipCode) {
alert(zipCode);
}
else {
alert('No result found!!');
}
} else {
alert('Enter proper address!!');
}
});
}
我认为与其依赖索引，不如更好地检查组件内的地址类型键。我通过使用开关盒解决了这个问题。
var address = '';
var pin = '';
var country = '';
var state = '';
var city = '';
var streetNumber = '';
var route ='';
var place = autocomplete.getPlace();
for (var i = 0; i < place.address_components.length; i++) {
var component = place.address_components[i];
var addressType = component.types[0];
switch (addressType) {
case 'street_number':
streetNumber = component.long_name;
break;
case 'route':
route = component.short_name;
break;
case 'locality':
city = component.long_name;
break;
case 'administrative_area_level_1':
state = component.long_name;
break;
case 'postal_code':
pin = component.long_name;
break;
case 'country':
country = component.long_name;
break;
}
}
我使用此代码来获取“邮政编码”和“位置”，但您可以使用它来获取任何其他字段，只需更改类型的值：
JAVASCRIPT
var address = results[0].address_components;
var zipcode = '';
var locality = '';
for (var i = 0; i < address.length; i++) {
if (address[i].types.includes("postal_code")){ zipcode = address[i].short_name; }
if (address[i].types.includes("locality")){ locality = address[i].short_name; }
}
places.getDetails( request_details, function(results_details, status){
// Check if the Service is OK
if (status == google.maps.places.PlacesServiceStatus.OK) {
places_postal = results_details.address_components
places_phone = results_details.formatted_phone_number
places_phone_int = results_details.international_phone_number
places_format_address = results_details.formatted_address
places_google_url = results_details.url
places_website = results_details.website
places_rating = results_details.rating
for (var i = 0; i < places_postal.length; i++ ) {
if (places_postal[i].types == "postal_code"){
console.log(places_postal[i].long_name)
}
}
}
});
This seems to work very well for me, this is with the new Google Maps API V3. If this helps anyone, write a comment, i'm writing my script as we speak... so it might change.
Romaine M.-谢谢！如果您只需要在 Google 返回的第一个结果中查找邮政编码，则只需执行 2 个循环：
for(var j=0;j < results[0].address_components.length; j++){
for(var k=0; k < results[0].address_components[j].types.length; k++){
if(results[0].address_components[j].types[k] == "postal_code"){
zipcode = results[0].address_components[j].long_name;
}
}
}
In PHP I use this code. Almost in every conditions it works.
$zip = $data["results"][3]["address_components"];
$zip = $index[0]["short_name"];
总而言之，这是一个很大的努力。至少使用 v2 API，我可以检索这些详细信息：
var place = response.Placemark[0];
var point = new GLatLng(place.Point.coordinates[1], place.Point.coordinates[0]);
myAddress = place.AddressDetails.Country.AdministrativeArea.SubAdministrativeArea.Locality.Thoroughfare.ThoroughfareName
myCity = place.AddressDetails.Country.AdministrativeArea.SubAdministrativeArea.Locality.LocalityName
myState = place.AddressDetails.Country.AdministrativeArea.AdministrativeAreaName
myZipCode = place.AddressDetails.Country.AdministrativeArea.SubAdministrativeArea.Locality.PostalCode.PostalCodeNumber
必须有一种更优雅的方法来检索单个 address_components 而无需通过您刚刚经历的循环柔术。
这个简单的代码对我有用
for (var i = 0; i < address.length; i++) {
alert(address[i].types);
if (address[i].types == "postal_code")
$('#postalCode').val(address[i].long_name);
if (address[i].types == "")
$('#country').val(address[i].short_name);
}
使用JSONPath，只需一行代码即可轻松完成：
var zip = $.results[0].address_components[?(@.types=="postal_code")].long_name;
return $http.get('//maps.googleapis.com/maps/api/geocode/json', {
params: {
address: val,
sensor: false
}
}).then(function (response) {
var model= response.data.results.map(function (item) {
// return item.address_components[0].short_name;
var short_name;
var st= $.each(item.address_components, function (value, key) {
if (key.types[0] == "postal_code") {
short_name= key.short_name;
}
});
return short_name;
});
return model;
});
据我所知，zip 是最后一个或最后一个。这就是为什么这是我的解决方案
const getZip = function (arr) {
return (arr[arr.length - 1].types[0] === 'postal_code') ? arr[arr.length - 1].long_name : arr[arr.length - 2].long_name;
};
const zip = getZip(place.address_components);
postal_code只需在所有类型中搜索，找到后返回。
const address_components = [{"long_name": "2b","short_name": "2b","types": ["street_number"]}, { "long_name": "Louis Schuermanstraat","short_name": "Louis Schuermanstraat", "types": ["route"]},{"long_name": "Gent","short_name": "Gent","types": ["locality","political" ]},{"long_name": "Oost-Vlaanderen","short_name": "OV","types": ["administrative_area_level_2","political"]},{"long_name": "Vlaanderen","short_name": "Vlaanderen","types": ["administrative_area_level_1","political"]},{"long_name": "België","short_name": "BE","types": ["country","political"]},{"long_name": "9040","short_name": "9040","types": ["postal_code"]}];
// address_components = results[0]address_components
console.log({
'object': getByGeoType(address_components),
'short_name': getByGeoType(address_components).short_name,
'long_name': getByGeoType(address_components).long_name,
'route': getByGeoType(address_components, ['route']).long_name,
'place': getByGeoType(address_components, ['locality', 'political']).long_name
});
function getByGeoType(components, type = ['postal_code']) {
let result = null;
$.each(components,
function() {
if (this.types.some(r => type.indexOf(r) >= 0)) {
result = this;
return false;
}
});
return result;
}<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>似乎现在最好从 restful API 中获取它，只需尝试：
https://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452&key= YOUR_KEY_HERE
使用 AJAX GET 调用非常完美！
就像是：
var your_api_key = "***";
var f_center_lat = 40.714224;
var f_center_lon = -73.961452;
$.ajax({ url: "https://maps.googleapis.com/maps/api/geocode/json?latlng="+f_center_lat+","+f_center_lon+"&key="+your_api_key,
method: "GET"
})
.done(function( res ) { if (debug) console.log("Ajax result:"); console.log(res);
var zipCode = null;
var addressComponent = res.results[0].address_components;
for (var x = 0 ; x < addressComponent.length; x++) {
var chk = addressComponent[x];
if (chk.types[0] == 'postal_code') {
zipCode = chk.long_name;
}
}
if (zipCode) {
//alert(zipCode);
$(current_map_form + " #postalcode").val(zipCode);
}
else {
//alert('No result found!!');
if (debug) console.log("Zip/postal code not found for this map location.")
}
})
.fail(function( jqXHR, textStatus ) {
console.log( "Request failed (get postal code via geocoder rest api). Msg: " + textStatus );
});
使用 jQuery
var postalObject = $.grep(results[0].address_components, function(n, i) {
if (n.types[0] == "postal_code") {
return n;
} else {
return null;
}
});
$scope.query.Pincode = postalObject[0].long_name;
我认为这是最准确的解决方案：
zipCode: result.address_components.find(item => item.types[0] === 'postal_code').long_name;
//autocomplete is the text box where u will get the suggestions for an address.
autocomplete.addListener('place_changed', function () {
//Place will get the selected place geocode and returns with the address
//and marker information.
var place = autocomplete.getPlace();
//To select just the zip code of complete address from marker, below loop //will help to find. Instead of y.long_name you can also use y.short_name.
var zipCode = null;
for (var x = 0 ; x < place.address_components.length; x++) {
var y = place.address_components[x];
if (y.types[0] == 'postal_code') {
zipCode = y.long_name;
}
}
});