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我正在尝试在 EF 中建立一个简单的多对一关系，并将其定义为：

type Car() =
    [<DefaultValue>] val mutable private id : int
    member x.ID with get() = x.id and set(v) = x.id <- v
    [<DefaultValue>] val mutable private carName : string
    member x.CarName with get() = x.carName and set(v) = x.carName <- v
    [<DefaultValue>] val mutable private dealer : Dealer
    member x.Dealer with get() = x.dealer and set(v) = x.dealer <- v

and Dealer() =
    [<DefaultValue>] val mutable private id : int
    member x.ID with get() = x.id and set(v) = x.id <- v
    [<DefaultValue>] val mutable private name : string
    member x.Name with get() = x.name and set(v) = x.name <- v
    [<DefaultValue>] val mutable private cars : seq<Car>
    member x.Cars with get() = x.cars and set(v) = x.cars <- v

type MyContext() = 
    inherit DbContext("MyContext")
    [<DefaultValue(true)>] val mutable private cars : DbSet<Car>
    member x.Cars with get() = x.cars and set(v) = x.cars <- v
    [<DefaultValue(true)>] val mutable private dealers : DbSet<Dealer>
    member x.Dealers with get() = x.dealers and set(v) = x.dealers <- v

并在控制台启动中以以下方式调用它：

let ctx = new MyContext()
Query.query <@ seq { for x in ctx.Cars do if x.CarName = "Volvo" then yield x.Dealer.Name } @>

以上将生成以下 SQL 查询：

SELECT 
[Extent2].[Name] AS [Name]
FROM  [dbo].[Cars] AS [Extent1]
LEFT OUTER JOIN [dbo].[Dealers] AS [Extent2] ON [Extent1].[Dealer_ID] = [Extent2].[ID]
WHERE N'Volvo' = [Extent1].[CarName]

现在是我的问题，为什么要使用 Car 类型中定义的 Dealer 并将其转换为Dealer_ID而不是DealerID?

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1 回答 1

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尝试使用StoreName DataAnnotation 属性或Fluent 映射 HasColumnName 方法指定此属性的显式映射。

于 2011-03-17T12:26:22.913 回答